Assignment_1_Solutions (1)

Assignment_1_Solutions (1) - 2-15 The value of M when by i...

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2-15) The value of M when by: i) reference is 2 ii) value-result is 3. Explanation: By-reference : X and y are pointing to N at the callee AR. Hence any change of value to either one of them (X or Y) results in an immediate change to the value of N, and consequently to the other formal value. If we change X, N will change and hence Y, and vise versa. X= 1 in SUB TEST changes the value of N at the main and Y at TEST to be 1. Hence, adding X to Y will result in 2 which will be stored in M (pointed to be Z). Hence M will end up having the value 2 . By-value-result: inside TEST, the execution of X=1 does not change N, hence Y remains 2. When we do Z = X + Y we are adding 1 + 2 and will end up having the value 3 upon existing the TEST subroutine. 2-16) i) If the addresses are computed once, on entry at the caller, then the program prints 10 , 20 , 11 . Steps: 1) At the caller side: “Call SUB (I, A(I))” the value of the actual parameters: I is 1 and A(1) = 10 2) at the callee side (inside SUB):
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