A CAR IS - let BC = x m now in right angle triangle ABC ,...

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the diagram of the problem may look like above A = position of the car B = level crossing C = position of the train clearly AB = distance of the car from crossing = 30 m            AC = the hypotenuse =distance of the train from car = 50 m now we have to find out BC which is the distance of the train fromthe crossing
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Unformatted text preview: let BC = x m now in right angle triangle ABC , we apply the Pythagorastheorem, AB 2 + BC 2 = AC 2 => 30 2 + x 2 =50 2 => x 2 =2500 - 900 = 1600 => x = 1600 = 40 = 40. ...................... [as length is always positive] Answer:) thedistance of the train from crossing is 40 m...
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This note was uploaded on 08/22/2011 for the course ACCOUNTING 201 taught by Professor Stevejoseph during the Winter '11 term at Aarhus Universitet.

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