Physics - Force F = M a = M V 2-U 2 2 S = 250000 2500 6000 = 104166.67 N = 104.17 kN(c time of acceleration t = V U a = 50 0.4167 = 120 s(d Work W

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Mass, M = 250000 kg     Initial velocity, U = 0 m/s     Final velocity, V = 50 m/s     Distance, S = 3000 m     (a)     Kinetic energy after the take off role = ( 1/2 )m V 2                                                           = 0.5 * 250000 * 2500                                                           = 312500000 J                                                           = 3.125 X 10  8  J (b)     Acceleration, a = [ ( V 2  -U 2  ) / 2 S ]                            = 2500 / 6000                            = 0.4167 m/s^2
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Unformatted text preview: Force, F = M a = M [ ( V 2 -U 2 ) / 2 S ] = 250000 * 2500 / 6000 = 104166.67 N = 104.17 kN (c) time of acceleration, t = ( V - U ) / a = 50 / 0.4167 = 120 s (d) Work, W = ( 1/2 ) M ( V 2 -U 2 ) = 3.125 X 10 8 Power, P = Work / time = 3.125 X 10 8 / 120 = 2.6 X 10 6 W...
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This note was uploaded on 08/22/2011 for the course ACCOUNTING 201 taught by Professor Stevejoseph during the Winter '11 term at Aarhus Universitet.

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