{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

8 enzyme kinetics - Chemical kinetics A B v = d[A dt = k[A...

Info icon This preview shows pages 1–9. Sign up to view the full content.

View Full Document Right Arrow Icon
Chemical kinetics A B v = d[A] / dt = k[A] first order A + B C v =d[A][B] / dt = k[A][B] second order K in terms of sec -1
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Reaction rate increases As [enzyme] increases
Image of page 2
During the course of an enzyme catalyzed reaction, the [substrate] decreases with time, and the [product] increases with time
Image of page 3

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
E + S Substrate E S E + S* E + P Products Active site An enzyme catalyzed reaction
Image of page 4
When [S] >> [E], then ES is formed rapidly and stays relatively constant throughout the course of the reaction. This is referred to as steady state conditions.
Image of page 5

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
The equation for an enzyme catalyzed reaction can be written k 1 k 2 E + S ES E + P k -1 The formation of product can be expressed as the rate equation v o = k 2 [ES] If all of the enzyme were complexed with substrate, then maximal velocity is defined as V max V max = k 2 [E T ] Where E T is total amount of enzyme, and E T = E + ES Or ES = E T -E
Image of page 6
If we know [ES], we could figure stuff out. Let’s go back to the course of an enzyme catalyzed reaction and look at [E] and [ES]. When [S] >> [E], then ES is formed rapidly and stays relatively constant throughout the course of the reaction. This is referred to as steady state conditions.
Image of page 7

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
We can figure out [ES].
Image of page 8
Image of page 9
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern