{1273816499437}.10 非线性补å&iquest

{1273816499437}.10 非线性补偿

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Unformatted text preview: 2010/05/09 ª* ª* øz ª* øz°· 0z° ª*(,v· á弊R+� ª á弊R+� ª* ª*ÐE 100 f × 100 80 ∂y = f (d ) ∂um 3 1 60 4 40 2 20 3.3 0 20 40 60 l × 100 80 100 4∙“*� ¨ 0 G2 u(t) Tsp TC Tm G1, T1 T 0 0 ��� �� ��������E������������@ Xÿu· : Èÿ4´ª* C1G1 (T − T1 ) = λG2 4×♠∗ ∪ Kp = : ∂T λ 1 = ∝ ∂G2 C1G1 G1 1 ð 0 G2 u(t) ∂T λ 1 Kp = = ∝ ∂G2 C1G1 G1 Tsp TC Tm G1, T1 T 0 0 ¨½°·ª* G1 ÐHvE Kp Kv ·ª* ÆG T G2 ·ª* ÆT . 2 ¨ � 0 u(t) G2 C1G1 (T − T1 ) = λG2 TC Tm G1, T1 T 0 : ¢«·ª i Tsp : ¢«·ª* ∂T λ 1 Kp = = ∝ ∂G2 C1G1 G1 0 � * “ • ‚ �—E� G1 Tp G2 ¢«·ª e ¢«·ª* i Kv ÀQ TC Fsp Fm FC 0 v(t) P1 0 P2 0 K c 2 K v K p 2 K m 2 >> 1 Q P¸·ª*ÐH E v K ' p2 = Kc2 Kv K p2 1 + Kc2 Kv K p2 K m2 ' K p2 ≈ 1 K m2 °• T2sp u(t) TC RVsp × RF FC RV T2 sp ∂RV ∝ RF ∂u C1 RF (T2 − T1 ) = λ RV ∂T2 1 ∝ ∂RV RF ∂T2 1 ∝ RF ∂u RF pH �� � 0 0 0 11 AC 10 SP 9 pH 0 � �� 8 7 6 0 5 4 3 pH�� b ¸ 0 1 0 20 ¢ È«· pH�� ¸ 30 /* 40 50 PH�� ������0u : (1) t = 60 min 0 pH 0 0 6.5 0 7.0; (2) t = 110 min> ø ª ·ª ·- >ø F1 0 30 L/min 0 15 L/min; (3) t = 160 min> ø ª ·pH 0 5 0 4.5; (4) t = 210 min 0 pH 0 11 0 10.5. pH «•“ ¢ �� ������@l• F � �� FC �� Rsp × u pHC ysp >›•“ * D ysp e0 e1 ym PID y u pH 00 pH ‚•“*��—E��� � ������7@�����@@�����@E����A � ��� “7@ ”@@@Ec � �� �� �������]‚ ? ˆ-·ª * 11 10 pH 9 8 0 7 ? ˆ-·ª 0 6 5 pH 4 3 ? ˆ-·ª 0 10 20 30 /* 40 50 D pHsp xsp PI D + u PH pH - xm [ pHm PH [ ] x = OH − − H + = f ( pH ) = 10 −14+ pH − 10 − pH � + R Š ¼ å á . 0 x 0 PH ð · ° a PH<0 0 x>0 0 PH>0 0 xð · ° a x=0 0 PH=7 0 x<0 0 ...
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This note was uploaded on 08/24/2011 for the course EE math 402 taught by Professor Na during the Fall '09 term at Zhejiang University.

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