Practice3 release

# Practice3 release - 2 π 6(ln(3 2-ln(2 2 4 R x = 2 x = 1 R...

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CME 100 Fall 2010 Vector Calculus for Engineers Page 1 of 1 Prof. Eric Darve Practice problems 3 For each question, choose the right answer. 1. 2 (cos( yx 2 ) + ln y ) /∂ x 2 = (a) - 2 y sin( yx 2 ) - 4 x 2 y 2 cos( yx 2 )) (b) - 2 sin( yx 2 ) - 2 x 2 y 2 cos( yx 2 )) (c) - 2 y sin( yx 2 ) - 2 x 2 y 2 cos( yx 2 )) (d) - 2 sin( yx 2 ) - 4 x 2 y 2 cos( yx 2 )) 2. 2 ( x y ) /∂ x y = (a) x y - 1 (1 / x + y ln x ) (b) x y - 1 (1 + y ) (c) x y - 1 (1 + y ln x ) (d) x y - 1 (1 / x + y ) 3. R x = π/ 3 x = 0 R y = 3 y = 2 cos( x ) + (ln y ) / y dy dx = (a) 3 / 2 + π/ 3 (ln(3) 2 - ln(2) 2 ) (b) 3 / 2 + π/ 6 (ln(3) 2 - ln(2) 2 ) (c) 1 / 2 + π/ 3 (ln(3) 2 - ln(2) 2 ) (d) 1
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Unformatted text preview: / 2 + π/ 6 (ln(3) 2-ln(2) 2 ) 4. R x = 2 x = 1 R y = 3 π/ 4 y = π/ 2 cos( y ) / ( x 2 sin( y )) dy dx = (a)-ln(2) / 2 (b) ln(2) / 4 (c) ln(2) / 2 (d)-ln(2) / 4 5. R x = 2 x = R y = 2 y = 1 ( xe x ) / y dy dx = (a) ln 2 ( e 2 + 1) (b) 2 ln 2 ( e 2 + 1) (c) ln 2 e 2 (d) 2 ln 2 e 2...
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