Assignment 1 JetCopies

Assignment 1 - Time 5 0.74 0.04 0.79 15.24 6 0.94 0.84 3.66 19.12 7 0.07 0.49 2.81 20.18 8 0.15 0.20 1.77 21.73 9 0.04 0.45 2.68 22.53 10 0.31 0.79

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ECO 550/Assignment 1 "Jet Copies Case Problem _Page 678-679 1 0.20 0.20 0.00 - .20 2 0.45 0.65 .21-.65 3 0.25 0.90 .66 - .90 4 0.10 1.00 .91 - 1.00 Breakdowns r1 r2 1 0.25 2.68 0.19 2 2 0.65 3.80 0.65 2 3 0.84 3.67 0.51 2 4 0.17 1.65 0.17 2 5 0.74 3.44 0.63 2 6 0.94 3.88 0.85 3 7 0.07 1.06 0.37 2 8 0.15 1.55 0.89 3 9 0.04 0.80 0.76 3 10 0.31 2.23 0.71 3 11 0.07 1.06 0.34 1 12 0.99 3.98 0.11 1 P(y) Cumulative Average Tim 0.20 0.20 0.20 Average Re 0.45 0.65 0.45 Average An 0.25 0.90 0.25 0.10 1.00 0.10 1.00 Breakdowns RN1 RN2 1 0.25 0.02 0.50 2.68 2 0.65 0.74 3.44 6.48 3 0.84 0.21 1.83 10.15 4 0.17 0.02 0.55 11.8 Machine Repair Number of Days Probability of Repair Time, P(y) Cumulative Probability Random Number Range, r2 Time Between Breakdowns Repair Time Repair Time, y Time Between Breakdowns Cumulative
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Unformatted text preview: Time 5 0.74 0.04 0.79 15.24 6 0.94 0.84 3.66 19.12 7 0.07 0.49 2.81 20.18 8 0.15 0.20 1.77 21.73 9 0.04 0.45 2.68 22.53 10 0.31 0.79 3.56 24.76 11 0.07 0.33 2.28 25.82 12 0.99 0.73 3.41 29.80 Cost $500 1,000 2.68 1,000 6.48 1,000 10.15 1,000 11.8 1,000 15.24 1,500 19.12 1,000 20.18 1,500 21.73 1,500 22.53 1,500 24.76 500 25.82 500 29.80 13,000 ime Between breakdowns 0.39 epair Time 2.17 nnual Cost 13,000 Costs 2 1,000 2 1,000 2 1,000 2 1,000 Cumlative Time Repair Time 2 1,000 3 1,500 2 1,000 3 1,500 3 1,500 3 1,500 1 500 1 500 13,000...
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This note was uploaded on 08/24/2011 for the course MAT 540 taught by Professor Azad during the Winter '10 term at Strayer.

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Assignment 1 - Time 5 0.74 0.04 0.79 15.24 6 0.94 0.84 3.66 19.12 7 0.07 0.49 2.81 20.18 8 0.15 0.20 1.77 21.73 9 0.04 0.45 2.68 22.53 10 0.31 0.79

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