lec06-handout-6up

# lec06-handout-6up - 6.003 Signals and Systems Lecture 6...

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6.003: Signals and Systems Lecture 6 September 29, 2009 1 6.003: Signals and Systems Continuous-Time Systems September 29, 2009 Mid-term Examination #1 Wednesday, October 7, 7:30-9:30pm, Walker Memorial. No recitations on the day of the exam. Coverage: DT Signals and Systems Lectures 1–5 Homeworks 1–4 Homework 4 will include practice problems for mid-term 1. However, it will not collected or graded. Solutions will be posted. Closed book: 1 page of notes ( 8 1 2 × 11 inches; front and back). Designed as 1-hour exam; two hours to complete. Review sessions during open oﬃce hours. Conﬂict? Contact [email protected] before Friday, October 2, 5pm. Multiple Representations of Discrete-Time Systems We have developed several useful representations for DT systems. Verbal descriptions: preserve the rationale. “To reduce the number of bits needed to store a sequence of large numbers that are nearly equal, record the ﬁrst number, and then record successive diﬀerences.” Diﬀerence equations: mathematically compact. y [ n ] = x [ n ] x [ n 1] Block diagrams: illustrate signal ﬂow paths. 1 Delay + x [ n ] y [ n ] Operator representations: analyze systems as polynomials. Y = (1 −R ) X Multiple Representations of Continuous-Time Systems Today we start to develop similarly useful representations for CT. Representing Continuous-Time Systems As with DT systems, we begin with verbal descriptions. Example: Leaky Tank r 0 ( t ) r 1 ( t ) h 1 ( t ) Verbal descriptions of continuous-time systems typically specify relations among signals (e.g., inputs and outputs) and their rates of change. “Water ﬂows into a tank at rate r 0 ( t ) and ﬂows out at a rate proportional to the depth of water in the tank. Determine . ..” Representing Continuous-Time Systems Translate the verbal description into diﬀerential equations. r 0 ( t ) r 1 ( t ) h 1 ( t ) Assume r 1 ( t ) hydraulic pressure at the bottom of the tank: r 1 ( t ) ρgh 1 ( t ) Height h 1 ( t ) will grow in proportion to r 0 ( t ) r 1 ( t ) : ˙ h 1 ( t ) r 0 ( t ) r 1 ( t ) Combining ﬁrst equation with second: ˙ r 1 ( t ) ˙ h 1 ( t ) r 0 ( t ) r 1 ( t ) ˙ r 1 ( t ) = α ( r 0 ( t ) r 1 ( t ) ) Derivatives play key role in CT, analogous to time shifts in DT.

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6.003: Signals and Systems Lecture 6 September 29, 2009 2 Check Yourself ˙ r 1 ( t ) = α ( r 0 ( t ) r 1 ( t ) ) r 0 ( t ) r 1 ( t ) h 1 ( t ) What are the dimensions of α ? Charactering Responses of CT Systems
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lec06-handout-6up - 6.003 Signals and Systems Lecture 6...

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