Version 078 – Make up 1 – laude – (51635)
1
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print-out
should
have
30
questions.
Multiple-choice questions may continue on
the next column or page – find all choices
before answering.
Constants
R
= 8
.
314 JK
-
1
mol
-
1
Definitions
Q
≡
[C]
c
[D]
d
[A]
a
[B]
b
G
≡
H
-
TS
K
w
≡
[H
+
][OH
-
]
pH
≡ -
log [H
+
]
pOH
≡ -
log [OH
-
]
Equations
Δ
G
=
Δ
H
-
T
Δ
S
ln
P
2
P
1
=
Δ
H
◦
vap
R
1
T
1
-
1
T
2
Π
=
MRT
Δ
T
b
=
iK
b
m
Δ
T
f
=
iK
f
m
P
i
=
P
◦
i
χ
i
P
=
i
P
i
q
=
mc
Δ
T
q
=
m
Δ
H
Δ
G
◦
=
-
RT
ln
K
K
=
e
-
Δ
G
◦
RT
ln
K
2
K
1
=
Δ
H
◦
R
1
T
1
-
1
T
2
Q
=
K
[at equil.]
[H
+
] = (
K
a
C
a
)
1
/
2
[OH
-
] = (
K
b
C
b)1/2Rank the following liquids in increasingorder of solubility in water (H2O):
[H
+
] =
K
a
(
C
a
/C
b
)
pH = p
K
a
+ log(
C
b
/C
a
)
[OH
-
] =
K
b
(
C
b
/C
a
)
pOH = p
K
b
+ log(
C
a
/C
b
)
001
6.0 points
Which line segments (
x
,
y
and
z
) corre-
spond to sublimation/deposition and vapor-
ization/condensation, respectively?
Carbon Dioxide
x
y
z
200
250
300
350
400
10
0
10
1
10
2
10
3
10
4
Pressure, bar
Temperature, K
1.
x
and
y
correct
2.
y
and
x
3.
not enough information
4.
z
and
x
5.
y
and
z
6.
x
and
z
7.
z
and
y
Explanation:
Sublimation/deposition
occurs
at
the
solid-gas
phase
boundary,
and
vaporiza-
tion/condensation occurs at the liquid-gas
phase boundary
002
6.0 points
CH
3
F,
(CH
3
)
2
NH, CH
3
Cl, CBr
4
.
1.
CH
3
Cl
<
CH
3
F
<
(CH
3
)
2
NH
<
CBr
4
2.
CH
3
F
<
(CH
3
)
2
NH
<
CBr
4
<
CH
3
Cl
3.
(CH
3
)
2
NH
<
CBr
4
<
CH
3
Cl
<
CH
3
F
4.
CBr
4
<
CH
3
Cl
<
CH
3
F
<
(CH
3
)
2
NH
correct
Version 078 – Make up 1 – laude – (51635)
2
Explanation:
0036.0 pointsWhat would be molar solubility of a very ex-pensive salt, awesomium, which is composedof 3 cations and 2 anion (X3Y2) and whoseKspis 0.00108?
1.
1.55 kcal
correct
2.
155 cal
3.
61.5 kcal
4.
6150 cal
5.
15.5 cal
Explanation:
10 g
H
2
0
◦
C
step 1
-→
10 g
H
◦
C
step 2
-→
10 g
H
