Make up 1-solutions

Make up 1-solutions - Version 078 Make up 1 laude (51635) Q...

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Version 078 – Make up 1 – laude – (51635) 1 This print-out should have 30 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. Constants R =8 . 314 JK - 1 mol - 1 Defnitions Q [C] c [D] d [A] a [B] b G H - TS K w [H + ][OH - ] pH ≡- log [H + ] pOH ≡- log [OH - ] Equations Δ G H - T Δ S ln ± P 2 P 1 ² = Δ H vap R ± 1 T 1 - 1 T 2 ² Π= MRT Δ T b = iK b m Δ T f = iK f m P i = P i χ i P = ³ i P i q = mc Δ T q = m Δ H Δ G = - RT ln K K = e - Δ G RT ln K 2 K 1 = Δ H R ± 1 T 1 - 1 T 2 ² Q = K [at equil.] [H + ]=( K a C a ) 1 / 2 [OH - ]=( K b C b ) 1 / 2 [H + ]= K a ( C a /C b ) pH = p K a +log( C b /C a ) [OH - ]= K b ( C b /C a ) pOH = p K b +log( C a /C b ) 001 6.0 points Which line segments ( x , y and z )co r r e - spond to sublimation/deposition and vapor- ization/condensation, respectively? Carbon Dioxide x y z 200 250 300 350 400 10 0 10 1 10 2 10 3 10 4 Pressure, bar Temperature, K 1. x and y correct 2. y and x 3. not enough inFormation 4. z and x 5. y and z 6. x and z 7. z and y Explanation: Sublimation/deposition occurs at the solid-gas phase boundary, and vaporiza- tion/condensation occurs at the liquid-gas phase boundary 002 6.0 points Rank the Following liquids in increasing order oF solubility in water (H 2 O): CH 3 ±, (CH 3 ) 2 NH, CH 3 Cl, CBr 4 . 1. CH 3 Cl < CH 3 ± < (CH 3 ) 2 NH < CBr 4 2. CH 3 ± < (CH 3 ) 2 NH < CBr 4 < CH 3 Cl 3. (CH 3 ) 2 NH < CBr 4 < CH 3 Cl < CH 3 ± 4. CBr 4 < CH 3 Cl < CH 3 ± < (CH 3
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Version 078 – Make up 1 – laude – (51635) 2 Explanation: According the axiom that ”like dissolves like,” the least miscible will be the non-polar molecule CBr 4 .T h em o s tm i s c i b l ew i l lb e (CH 3 ) 2 NH, which exhibits hydrogen bonding just as water does. Between the two polar molecules, CH 3 Fisthemorepo larandthus the more miscible because of the greater elec- tronegativity di±erence. 003 6.0 points What would be molar solubility of a very ex- pensive salt, awesomium, which is composed of 3 cations and 2 anion (X 3 Y 2 )andwhose K sp is 0 . 00108? 1. 0 . 1M correct 2. 0 . 06 M 3. 1M 4. 0 . 033 M Explanation: For a salt of the form X 3 Y 2 molar solubility = x = ± K sp 27 · 4 ² 0 . 2 x= ± 0 . 00108 27 · 4 ² 0 . 2 =0 . 1M 004 6.0 points The speci²c heat of water is 1 . 00 cal / g · C, the heat of vaporization of water is 540 cal/g, and the heat of fusion of water is 80 cal/g. How much heat would be required to convert 10 grams of ice at 0 Cto10gramso fwaterat 75 C? 1. 1.55 kcal correct 2. 155 cal 3. 61.5 kcal 4. 6150 cal 5. 15.5 cal Explanation: 10 g H 2 O(s) 0 C step 1 -→ 10 g H 2 O( ± ) 0 C step 2 -→ 10 g H 2 O( ± ) 75 C Step 1: 80 cal g (10 g) = 800 cal Step 2: 1cal g · C (10 g)(75 -
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This note was uploaded on 08/24/2011 for the course CH 302 taught by Professor Holcombe during the Spring '07 term at University of Texas.

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Make up 1-solutions - Version 078 Make up 1 laude (51635) Q...

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