q1p302key - CH302 TA Practice Quiz 1 Answer Key 1 An...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
CH302 TA Practice Quiz 1 Answer Key 1. An unknown liquid is 2000 Pa at 25 oC and 7500 Pa at 50 oC. Based on the Clausius- Clapeyron equation which expression below could be used to solve for the enthalpy of vaporization ( Ʃ H vap ) of the unknown liquid? 1. [(8.314 J/mol*K)ln(7500 Pa /2000 Pa)] / [(1/50) ± (1/25)] = Ʃ H vap 2. -[(8.314 J/mol*K)ln(7500 Pa /2000 Pa)] / [(1/323) ± (1/298)] = Ʃ H vap 3. [(8.314 J/mol*K)ln(7500 Pa /2000 Pa)] / [(1/323) ± (1/298)] = Ʃ H vap 4. -[(8.314 J/mol*K)ln(7500 Pa /2000 Pa)] / [(1/50) ± (1/25)] = Ʃ H vap 5. -[(8.314 J/mol*K)ln(7500 Pa /2000 Pa)] / [(1/323) + (1/298)] = Ʃ H vap Explanation: Solve the Clausius-Clapeyron equation to express Ʃ Hvap in terms of the other variables. Plug in the given values, but remember to convert temperature to Kelvin. 2. Sketch a phase diagram using the following information: triple point at 45 atm and 310 K. Critical point at 65 atm and 575 K. The diagram intersects the Y axis at 5 atm. Y axis: 0 to 70 atm. X-axis: 0 to 600 K. Which of the following would result in sublimation?
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Page1 / 3

q1p302key - CH302 TA Practice Quiz 1 Answer Key 1 An...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online