{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Solutions7

# Solutions7 - Problem 6.6[3 Given Velocity field Find...

This preview shows pages 1–2. Sign up to view the full content.

Problem 6.6 [3] Given: Velocity field Find: Expressions for local, convective and total acceleration; evaluate at several points; evaluate pressure gradient Solution: The given data is A 2 1 s = ω 1 1 s = ρ 2 kg m 3 = u A x sin 2 π ω t ( ) = v A y sin 2 π ω t ( ) = Check for incompressible flow x u y v + 0 = Hence x u y v + A sin 2 π ω t ( ) A sin 2 π ω t ( ) = 0 = Incompressible flow The governing equation for acceleration is The local acceleration is then x - component t u 2 π A ω x cos 2 π ω t ( ) = y - component t v 2 π A ω y cos 2 π ω t ( ) = For the present steady, 2D flow, the convective acceleration is x - component u x u v y u + A x sin 2 π ω t ( ) A sin 2 π ω t ( ) ( ) A y sin 2 π ω t ( ) ( ) 0 + = A 2 x sin 2 π ω t ( ) 2 = y - component u x v v y v + A x sin 2 π ω t ( ) 0 A y sin 2 π ω t ( ) ( ) A sin 2 π ω t ( ) ( ) + = A 2 y sin 2 π ω t ( ) 2 = The total acceleration is then x - component t u u x u + v y u + 2 π A ω x cos 2 π

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 5

Solutions7 - Problem 6.6[3 Given Velocity field Find...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online