{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

329fall08hw13sol

329fall08hw13sol - ECE-329 Fall 2008 Homework 13 Solution...

This preview shows pages 1–3. Sign up to view the full content.

ECE-329 Fall 2008 Homework 13 — Solution December 5, 2008 1. Problem 1 r=2 r=0 r=1 r= x=1/2 x=0 x=1 x=2 x=-1/2 x=-1 x=-2 1

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
ECE-329 Fall 2008 2. Problem 2 a) Normalized load impedance z L = 100 50 = 2 Load reflection coefficient Γ L = 2 - 1 2+1 = 1 3 Generalized reflection coefficient Γ( l ) = 1 3 e - j 4 π/ 5 = 1 3 e - j 2 . 513 Normalized input impedance at the generator z ( l ) = 1+Γ( l ) 1 - Γ( l ) = 0 . 539 - j 0 . 237 Input impedance at the generator Z ( l ) = 50 · z ( l ) = 26 . 93 - j 11 . 87 Ω b) Voltage phasor at the generator V ( l ) = 10 · Z ( l ) 50+ Z ( l ) = 3 . 78 e - j 0 . 262 V c) Voltage phasor of incident wave V + = 5 e - j 4 π/ 5 = 5 e - j 2 . 513 V d) Voltage phasor at the load V (0) = V + (1 + Γ L ) = 20 3 e - j 4 π/ 5 = 6 . 66 e - j 2 . 513 V e) Current phasor at the load I (0) = V (0) Z L = 1 15 e - j 4 π/ 5 = 0 . 066 e - j 2 . 513 A Γ (0) Γ ( l ) 3. Problem 3 a) Normalized load impedance z L = 50 50 = 1 Load reflection coefficient Γ L = 1 - 1 1+1 = 0 , Generalized reflection coefficient Γ( l ) = Γ L = 0 Input impedance at the generator Z ( l ) = Z o = 50 Ω b) Voltage phasor at the generator V ( l ) = 10 · Z ( l ) 50+ Z ( l ) = 5 V c) Voltage phasor of incident wave V + = 5 e - j 4 π/ 5 V
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Page1 / 5

329fall08hw13sol - ECE-329 Fall 2008 Homework 13 Solution...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online