PracticeMidterm - LS4 MIDTERM I INSTRUCTORS Steve...

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Unformatted text preview: LS4 MIDTERM I INSTRUCTORS: Steve Jacobsen/Lianna Johnson Wed, Oct 29, 2003 NAME:_________________________________ (last) (first) ID #___________________________________ Circle TA name Stacey Danny Shaun Brian Amy Devon Carey Elaine Nikki John INSTRUCTIONS 1. This exam is 11 pages long including this front page. Before starting make sure you have all the pages. Put your name on each page!!!!!!!!! 2. No credit will be given for an illegible answer. Regrades will only be considered for answers written in pen. 3. You may use a calculator. 4. Show all your work!! You will not be given credit for answers alone. 5. May the force be with you! QUESTION VALUE SCORE 1 14 2 12 3 12 4 17 5 17 6 15 7 16 8 15 9 16 10 16 2 Name ____________________________________________ ID#______________________ (last) (first) 1. (14 points) Mendel/Probabilities. a) (7 points). Two pure breeding strains of peas, one giving round, yellow seeds, and the other wrinkled, green seeds, were crossed and all the resulting peas were round and yellow. These F1 seeds were then planted and the flowers self- fertilized. What proportion of the F 2 offspring will be phenotypically identical to neither of the original parental strains? (Assume independent assortment, complete dominance, and no linkage). 9 R-Y- (like one parent) 3 rrY- 3 R-yy 1 rryy (like the other parent) Therefore, 6/16 b) (7 points). In tomatoes, red fruit is dominant to yellow fruit and purple stems are dominant to green stems. The progeny of one mating consisted of 610 red fruit, purple stem plants, 656 red fruit, green stem plants, 220 yellow fruit, purple stem plants, and 194 yellow fruit, green stem plants. What was the genotype of each of the two parents in this cross? Red = R yellow = r purple = P green = p 610 R-P- 656 R-pp 220 rrP- 194 rrpp Therefore, parents must have been RrPp and Rrpp. 3 Name ____________________________________________ ID#______________________ (last) (first) 2. (12 points). Consider the following pedigree for a rare disease: a) (4 points) What is the mode of inheritance (X-linked recessive, X-linked dominant, autosomal recessive, autosomal dominant)? How do you know? autosomal dominant b) (4 points) What is the genotype of individual III-1? Aa c) (4 points) If this individual (III-1) marries an unaffected male, what is the probability that they will have an affected boy? p(Aa) X p(boy) .5 X .5 = .25 4 Name ____________________________________________ ID#______________________ (last) (first) 3. (12 points). Alkaptonuria is a rare recessive disorder that causes mental retardation in patients exposed to excess dietary phenylalanine. A woman whose maternal grandfather had alkaptonuria, and a man whose mother has alkaptonuria are concerned about the risk of passing this trait to their children. No other members of the family are known to be affected.family are known to be affected....
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This note was uploaded on 08/26/2011 for the course LIFE SCIEN LS4 taught by Professor Jacobsen during the Spring '11 term at UCLA.

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PracticeMidterm - LS4 MIDTERM I INSTRUCTORS Steve...

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