153A_Final_S10_answers

153A_Final_S10_answers - Chem 153A, Spring 2010 Final Exam...

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Chem 153A, Spring 2010 Final Exam Answer Key Part I (Answer Sheet 1) 1. a. (2) B b. (3) In eukaryotes, mitochondria are required for the oxidation of amino acids and fatty acids to yield ATP. In contrast, sugars can yield ATP through fermentation. 2. a. (3) Although in the aldolase reaction, glucose carbons 4-6 yield GAP (and 1-3 yield DHAP), GAP can be rapidly isomerized to DHAP by TIM. b. (2) C1 3. (2) False – no TPP 4. (2) True 5. (2) True 6. (2) False – Coenzyme A is an acyl carrier. 7. (2) True 8. (20) 1) A, E, I 2) C, D, E, G, I 3) A, B, C, E, I 4) B, F, G, I 5) C, I 6) D, F, I 9. (4) a, f, h 10. a. (3) Creatine phosphate b. (3) ATP + H 2 O ADP + P i ΔG' ° = -30.5 kJ/mol + creatine + P i creatine phosphate + H 2 O ΔG' ° = +43.1 kJ/mol = ATP + creatine ADP + creatine phosphate ΔG' ° = +12.6 kJ/mol c. (3) [ATP] is high relative to [ADP] d. (5) Since the reaction is close to equilibrium, rising ATP levels (= falling ADP levels) will lead ATP to get used to make creatine phosphate, and falling ATP levels (= rising ADP levels) will lead creatine phosphate to get used to phosphorylate ADP. e. (4) ΔG = ΔG' ° + RT lnQ, so lnQ = (ΔG – ΔG' ° )/RT Q = ([ADP][creatine phosphate])/([ATP][creatine]) = e (ΔG – ΔG' ° )/RT [creatine phosphate]/[creatine] = ([ATP]/[ADP]) e (ΔG – ΔG' ° )/RT = 10 e (0 kJ/mol – 12.6 kJ/mol)/(0.00831 kJ/mol·K)(310K) = 0.075 f. (3) In aerobic exercise, creatine phosphate is used up quickly, and the majority of ATP is regenerated through
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153A_Final_S10_answers - Chem 153A, Spring 2010 Final Exam...

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