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Unformatted text preview: = c100 39632 = * = c 100 39632 1570536900 c. Use the value of C you found in the previous question to determine how much the object would weigh in i. Death Valley (282 feet below sea level). =-. = distance from center 3963 28252803962 946591 miles 20924358 feet = w cr² = * .- = . w 1570536900 3962 9465912 2 100 0026954lbs ii. the top of Mount McKinley (20,320 feet above sea level). = + = . distance from center 3963 204305280 3966 869318 = w cr-2 w=1570536900*3966.869318-2 =99.80501344lbs MAT/117 2. The equation gives the distance, D , in miles that a person can see to the horizon from a height, h , in feet. a. Solve this equation for h . = . D 1 2h = . h D1 2 . hD1 2² b. Long’s Peak in Rocky Mountain National Park, is 14,255 feet in elevation. How far can you see to the horizon from the top of Long’s Peak? Can you see Cheyenne, Wyoming (about 89 miles away)? Explain your answer. = . = . D 1 214255 143 27 miles MAT/117...
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- Spring '10
- Oceanography, sea level, Axia College Material, Above mean sea level