# project3 - as the superposition of, and: (eqn. 5) Average...

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4165 4165 4165 UFID 0087-1745 1. Determine the shear flow due to V and T. Shear flow: (eqn. 1) Finding the Moment of inertia: Moment of inertia about z: (eqn. 2) Now, we find for each S section: At: Replacing and into equation 1 we get:

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W do the same process for and. The results are as follows: Since passes through the shear center, the twist angle is equal to zero: (eqn. 3) At: At:
At: At: Replacing those values into equation 3: Solving for: Until now, we have solved for the shear flow due to the sear force. Now, we have to find the shear flow due to the torque T: (eqn. 4) Where:

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From phase 2 of this project, we found and. Thus: and We are now able to solve for the total shear flow due to V and T. The actual shear flow can be considered

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Unformatted text preview: as the superposition of, and: (eqn. 5) Average case Elliptic case 2. Superimpose the two shear flows and draw the shear flow diagram on the root section Figure 1. Shear flow diagram 3. Calculate the location and magnitude of the maximum shear stress. The maximum shear stress happens at the maximum shear flow, which is located in the middle of contour, where inches as shown in figure 1. Hence: (eqn. 6) Average case psi Elliptic case psi 4. Determine the maximum flexural stress The maximum flexural stress should be at the top and bottom sections of the root section. (eqn. 7) The maximum moment was calculated to be and lb-in. Average case...
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## This note was uploaded on 08/27/2011 for the course AEROSPACE 3115C taught by Professor Bakcer during the Spring '10 term at University of Florida.

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project3 - as the superposition of, and: (eqn. 5) Average...

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