2-58 - Chapter 2, Solution 58 The resistor of the bulb is...

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Chapter 2, Solution 58 The resistor of the bulb is 120/(0.75) = 160 Ω Once the 160 Ω and 80 Ω resistors are in parallel, they have the same voltage 120V. Hence the current through the 40
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This note was uploaded on 08/27/2011 for the course EEL 3111C taught by Professor Srivastava during the Spring '08 term at University of Florida.

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