4-32 - x 2.5i x = 0, or i x = 1.6 A (a) 15 40 5i x 60V + 50...

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Chapter 4, Solution 32. As shown in Fig. (a), we transform the dependent current source to a voltage source, In Fig. (b), 50||50 = 25 ohms. Applying KVL in Fig. (c), -60 + 40i
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Unformatted text preview: x 2.5i x = 0, or i x = 1.6 A (a) 15 40 5i x 60V + 50 + 10 i x + (c) 15 2.5i x 60V + 25 i x 60V + (b) 15 50 0.1i x 50...
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