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HW_11_all - Dynamic Force Analysis 6 1 Force Analysis...

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Dynamic Force Analysis 1 6 Force Analysis Homework 11: Joint reaction forces and equilibrium moment Problem 6.3 The mechanism in Fig. P6.3 has the dimensions: AB =200 mm, AC =600 mm, BD =1000 mm, L a =150 mm, L b =250 mm, and EF =600 mm. The driver link 1 rotates with a constant angular speed of n =60 rpm. The links are homogeneous rectangular prisms made of steel with the width h = 0 . 01 m and the depth d = 0 . 001 m. The steel sliders 3 and 4 have the width w Slider = 0 . 05 m, the height h Slider = 0 . 02 m, and the depth d = 0 . 001 m. The density of the material is ρ Steel = 8000 kg/m 3 and the gravitational acceleration is g = 9 . 807 m/s 2 . The external moment on 5 is opposed to the motion of the link M ext = M 5 ext = -| M ext | ω 5 | ω 5 | , where | M ext | = 900 N · m. Find the equilibrium moment on link AB and the joint reaction forces for φ = φ 1 =120 . For φ =120 the kinematics of the mechanism are given by: x B =-0.1 m, y B =0.173205 m, x C =-0.6 m, y C =0 m, x D =-1.04491 m, y D =-0.154122 m, φ 2 =0.333473 rad, φ 5 =0.940376 rad, ˙ x B 1 =-1.08828 m/s, ˙ y B 1 =-0.628319 m/s, ¨ x B 1 =3.94784 m/s 2 , ¨ y B 1 =-6.83786 m/s 2 , v C 2 C 3 =-1.23399 m/s, ω 2 =-0.448799 rad/s,
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