HW_vel_56 - 1 4 Velocity and Acceleration Analysis 4...

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4 Velocity and Acceleration Analysis 1 4 Homework 6: Velocity and Acceleration Analysis Problem 4.5 The mechanism in Fig. P4.5 has the dimensions: AB =200 mm, AC =600 mm, BD =1000 mm, L a =150 mm, and L b =250 mm. The driver link 1 rotates with a constant angular speed of n =60 rpm. Find the velocities and the accel- erations of the mechanism for φ = φ 1 =120 . For φ =120 the position of the mechanism is given by: x B =-0.1 m, y B =0.173205 m, x C =-0.6 m, y C =0 m, x D =-1.04491 m, y D =-0.154122 m, φ 2 =0.333473 rad, φ 5 =0.940376 rad. 0 y φ A x 1 L a L b D C B E 3 2 4 5 0 0 n Figure P4.5: Mechanism P4.5
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4 Velocity and Acceleration Analysis 2 Results ˙ x B 1 =-1.08828 m/s, ˙ y B 1 =-0.628319 m/s, ¨ x B 1 =3.94784 m/s 2 , ¨ y B 1 =-6.83786 m/s 2 , v C 2 C 3 =-1.23399 m/s, ω 2 =-0.448799 rad/s, ˙ x D 2 =-1.23518 m/s, ˙ y D 2 =-0.204243 m/s, a cor C 2 C 3 x =-0.362557 m/s 2 , a cor C 2 C 3 y =1.04661 m/s 2 , a C 2 C 3 =1.59873 m/s 2 , α 3 =- 16.7458 rad/s 2 , ¨ x D 2 =-1.34318 m/s 2 , ¨ y D 2 =9.05135 m/s 2 , v D 5 D 4 =0.893105 m/s, ω 5 =-1.75371 rad/s, a cor D 5 D 4 x =2.53037 m/s 2 , a cor D 5 D 4 y =-1.84656 m/s 2 , a D 5 D 4 =- 4.98108m/s 2 , α 5 =-6.57248 rad/s 2 . rA = [0, 0, 0] (m)
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This note was uploaded on 08/29/2011 for the course MECH 2120 taught by Professor Gabale,a during the Summer '08 term at Auburn University.

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HW_vel_56 - 1 4 Velocity and Acceleration Analysis 4...

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