Spectroscopy (v.1 KEY) - Second Exam Chem 241 February 24,...

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1 Second Exam February 24, 2010 Name: _________KEY-1 ____________ Chem 241 Professor Jorgenson (please print full name) Honor Code Pledge: _____________________________ ( s i g n a t u r e ) c = 3.00 x 10 8 meters/second h = 6.63 x 10 -34 joule-seconds N= 6.022 x 10 23 mole -1 = c/n E = h A = bC A = - Log (T) = 2 - Log (%T) E n e r g y ( J o u l s ) S 0 S 1 T 1 1 2 3 4 5 7 8 Molecular Energy Level Diagram (energies listed for a single molecule) 9 6 10 10.0 x10 -19 2.0 x10 -19 4.0 x10 -19 6.0 x10 -19 8.0 x10 -19 0x10 -19
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2 Name: __________________________________ (please print full name) Answer Page: Using BLOCK CAPITAL LETTERS write the letter of your answer to each problem in the space provided below 1. _____ 2. _____ 3. _____ 4. _____ 5. _____ 6. _____ 7. _____ 8. _____ 9. _____ 10. _____ 11. _____ 12. _____ 13. _____ 14. _____ 15. _____ 16. _____ 17. _____ 18. _____ 19. _____ 20. _____ 1) Referring to the energy level diagram on the front page of the exam, the process indicated by the number 8 is: A) absorption B) fluorescence C) singlet state D) intersystem crossing E) vibrational relaxation F) triplet state G) internal conversion H) phosphorescence 2) Referring to the energy level diagram on the front page of the exam, the process indicated by the number 7 is: A) internal conversion B) phosphorescence C) vibrational relaxation D) triplet state E) absorption F) fluorescence G) singlet state H) intersystem crossing 3) Referring to the energy level diagram on the front page of the exam, the light absorbed by this molecule corresponds to: A) X-rays B) ultraviolet C) infrared D) gamma-rays E) radiowaves F) microwaves 4) Referring to the energy level diagram on the front page of the exam, the process indicated by the number 4 is: A) absorption B) fluorescence C) singlet state D) phosphorescence E) internal conversion F) intersystem crossing G) vibrational relaxation H) triplet state 5) Referring to the energy level diagram on the front page of the exam, calculate the wavelength of light this molecule emits by fluorescence. Express your answer in units of nanometers. A) 2.6 x 10 2 nm B) 5.0 x 10 6 nm C) 3.8 x 10 2 nm D) 4.4 x 10 2 nm E) 1.5 x 10 15 nm F) 1.1 x 10 15 nm G) 5.3 x 10 2 nm H) 3.3 x 10 2 nm
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3 6) Referring to the energy level diagram on the front page of the exam: when this molecule absorbs light and emits fluorescence, how much of the absorbed light energy is ultimately converted into heat in the surroundings? Express your answer in units of Joules. A) 1.5 x 10 -19 J B) 2.0 x 10 -19 J C) 4.0 x 10 -19 J D) 3.0 x 10 -19 J E) 1.0 x 10 -19 J F) 1.0 x 10 -18 J G) 8.0 x 10 -19 J H) 6.0 x 10 -19 J 7) The regions of the electromagnetic spectrum, in order of highest to lowest photon energy, are: A) radiowave, microwave, infrared, visible, ultraviolet, X-ray, gamma-ray B) gamma-ray, X-ray, ultraviolet, visible, infrared, microwave, radiowave C) microwave, radiowave, infrared, visible, ultraviolet, X-ray, gamma-ray D) radiowave, microwave, infrared, visible, ultraviolet, gamma-ray, X-ray
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This note was uploaded on 08/27/2011 for the course CHEM 101 taught by Professor Smith during the Spring '11 term at East Carolina University .

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Spectroscopy (v.1 KEY) - Second Exam Chem 241 February 24,...

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