force_half_final_fbd

force_half_final_fbd - force_half_final_fbd.nb 1 !AB !...

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Force analysis via FBD of individual links ! AB ! 0.14, AC ! 0.06, CF ! 0.25, h ! 0.01, d ! 0.01, hSlider ! 0.02, wSlider ! 0.05, ro ! 8000, g ! 9.807, Me ! 1000., phi " t # ! 1.0472, phi " " t # ! 52.3599, phi "" " t # ! 0 $ Inertia forces and moments Link 1 m1 # ro AB h d # 0.112 " kg # IC1 # m1 % AB^2 $ h^2 12 # 0.000183867 " kg m^2 # Fin1 #% m1 aC1 # ! 10.7469, 18.6142, 0 $" N # F1 # Fin1 $ G1 # ! 10.7469, 17.5158, 0 $" N # Min1 # M1 #% IC1 alpha10 # ! 0, 0, 0 $" Nm # Link 2 m2 # ro hSlider wSlider d # 0.08 " kg # IC2 # m2 % hSlider^2 $ wSlider^2 12 # 0.0000193333 " kg m^2 # Fin2 #% m2 aC2 # ! 15.3527, 26.5917, 0 $" N # F2 # Fin2 $ G2 # ! 15.3527, 25.8071, 0 $" N # Min2 # M2 #% IC2 alpha20 # ! 0, 0, % 0.0475952 $" Nm # Link 3 m3 # ro CF h d # 0.2 " kg # IC3 # m3 % CF^2 $ h^2 12 # 0.00104333 " kg m^2 # Fin3 #% m3 aC3 # ! 145.238, 45.2941, 0 $" N # F3 # Fin3 $ G3 # ! 145.238, 43.3327, 0
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This note was uploaded on 08/29/2011 for the course MECH 6420 taught by Professor Marghitu during the Summer '11 term at University of Florida.

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force_half_final_fbd - force_half_final_fbd.nb 1 !AB !...

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