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Unformatted text preview: XZ + R 2 = 0 Z, horizontal: cos(60°)F XZ + F YZ + R 3 = 0 Letting the vector of unknowns be [F XY F XZ F YZ R 1 R 2 R 3 ] T , the coefficient matrix is sin(60°) sin(60°) cos(60°)cos(60°) sin(60°) 1 cos(60°) 1 sin(60°) 1 cos(60°) 1 1 with righthand side [500 0 0 0 0 0] T . (b) Because each equation only involves two or three unknown forces, we can solve for them one by one: From the second equation, F XY = F XZ so, from the first equation, F XY = F XZ = 500 / √3 N. From the third equation, R 1 = 250 N From the fifth equation, R 2 = 250 N From the fourth equation, F YZ = 250 / √3 N Finally, from the sixth equation, R 3 = 0 N. 4] The rowsum norm of A is the maximum sum of each row's absolute values, which is 23. Similarly, the rowsum norm of A1 is 6.125. The rowsumnorm condition number of A (or A1 ) is the product of these two norms, or 140.875....
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 Spring '11
 Lybas
 Numerical Analysis, SEPTA Regional Rail, Complex number, Jaguar Racing, University City

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