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Unformatted text preview: Calculation of Settlement H ∆ S z x Settlement of a single layer H ∆ S z x Settlement of a single layer ε ε zz v S H e e = = = + ∆ ∆ 1 H ∆ S z x (1) Settlement of a single layer ε ε zz v S H e e thus S e H e = = = + = + ∆ ∆ ∆ ∆ 1 1 sublayer 1 sublayer 2 sublayer n Notation e voids ratio at the centre of layer i e increase in voids ratio at the centre of layer i H thickness of layer i i i i = = ∆ Soil profile divided into a number of sublayers Thus For sub layer i S e H e i i i i = + ∆ ∆ 1 Soil profile divided into a number of sublayers (2) Thus For sub layer i S e H e so that Total Settlement S S e H e i i i i i n i i i n = + = ∑ = + ∑ ∆ ∆ ∆ ∆ 1 1 1 1 [ ] Soil profile divided into a number of sublayers 5m 4m 4m Gravel Clay A B Layered soil deposit 2m Example of Settlement Calculation W.T. 5m 4m 4m Gravel Clay A B Layered soil deposit 2m Stress increase at A=100 KPa Stress increase at B= 60 KPa Example of Settlement Calculation Properties Gravel Relatively incompressible γ γ dry sat kN m kN m = = 18 22 3 3 / ; / Example of Settlement Calculation Properties Gravel Relatively incompressible Clay e 0 = 0.8 G s = 2.7 C c = 0.20; C r = 0.05 γ γ dry sat kN m kN m = = 18 22 3 3 / ; / Example of Settlement Calculation Voids Skeletal material V s =1 m 3 Distribution of Volume Example of Settlement Calculation Voids Skeletal material V s =1 m 3 Distribution of Volume Distribution of Weight Example of Settlement Calculation Voids Skeletal material V s =1 m 3 Distribution of Volume Distribution of Weight Example of Settlement Calculation γ sat w s v s W W V V kN m kN m = + + = + + = 7 84 26 46 08 1 19 06 3 3 . . . / . / Voids Skeletal material V s =1 m 3 Distribution of Volume Distribution of Weight Example of Settlement Calculation γ γ γ sat w s v s sat s w W W V V kN m kN m or G e e kN m = + + = + + = = + + = 7 84 26 46 08 1 19 06 1 19 06 3 3 3 . . . / . / ( ) . / The next step is to calculate the initial and final effective stress at the centre of each sublayer Example of Settlement Calculation The next step is to calculate the initial and final effective stress at the centre of each sublayer Example of Settlement Calculation • Initial State at A Total stress σ zz = 2x 18 + 3 x 22 + 2 x × 19.06 = 140.12 kPa The next step is to calculate the initial and final effective stress at the centre of each sublayer Example of Settlement Calculation • Initial State at A Total stress Pore water pressure u w = 5 x 9.8 kPa = 49 kPa (3a) σ zz = 2x 18 + 3 x 22 + 2 x × 19.06 = 140.12 kPa The next step is to calculate the initial and final effective stress at the centre of each sublayer Example of Settlement Calculation • Initial State at A Total stress Pore water pressure (3a) Effective stress σ′ zz = σ zz  u w = 140.12  49 = 91.12 kPa σ zz = 2x 18 + 3 x 22 + 2 x × 19.06 = 140.12 kPa u w = 5 x 9.8 kPa = 49 kPa The next step is to calculate the initial and final effective stress at...
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This note was uploaded on 08/30/2011 for the course CIVL 2410 taught by Professor Dairey during the Three '11 term at University of Sydney.
 Three '11
 DAirey

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