# sma09 - Calculation of Settlement H ∆ S z x Settlement of...

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Unformatted text preview: Calculation of Settlement H ∆ S z x Settlement of a single layer H ∆ S z x Settlement of a single layer ε ε zz v S H e e = = =- + ∆ ∆ 1 H ∆ S z x (1) Settlement of a single layer ε ε zz v S H e e thus S e H e = = =- + =- + ∆ ∆ ∆ ∆ 1 1 sub-layer 1 sub-layer 2 sub-layer n Notation e voids ratio at the centre of layer i e increase in voids ratio at the centre of layer i H thickness of layer i i i i = = ∆ Soil profile divided into a number of sub-layers Thus For sub layer i S e H e i i i i- =- + ∆ ∆ 1 Soil profile divided into a number of sub-layers (2) Thus For sub layer i S e H e so that Total Settlement S S e H e i i i i i n i i i n- =- + = ∑ =- + ∑ ∆ ∆ ∆ ∆ 1 1 1 1 [ ] Soil profile divided into a number of sub-layers 5m 4m 4m Gravel Clay A B Layered soil deposit 2m Example of Settlement Calculation W.T. 5m 4m 4m Gravel Clay A B Layered soil deposit 2m Stress increase at A=100 KPa Stress increase at B= 60 KPa Example of Settlement Calculation Properties Gravel Relatively incompressible γ γ dry sat kN m kN m = = 18 22 3 3 / ; / Example of Settlement Calculation Properties Gravel Relatively incompressible Clay e 0 = 0.8 G s = 2.7 C c = 0.20; C r = 0.05 γ γ dry sat kN m kN m = = 18 22 3 3 / ; / Example of Settlement Calculation Voids Skeletal material V s =1 m 3 Distribution of Volume Example of Settlement Calculation Voids Skeletal material V s =1 m 3 Distribution of Volume Distribution of Weight Example of Settlement Calculation Voids Skeletal material V s =1 m 3 Distribution of Volume Distribution of Weight Example of Settlement Calculation γ sat w s v s W W V V kN m kN m = + + = + + = 7 84 26 46 08 1 19 06 3 3 . . . / . / Voids Skeletal material V s =1 m 3 Distribution of Volume Distribution of Weight Example of Settlement Calculation γ γ γ sat w s v s sat s w W W V V kN m kN m or G e e kN m = + + = + + = = + + = 7 84 26 46 08 1 19 06 1 19 06 3 3 3 . . . / . / ( ) . / The next step is to calculate the initial and final effective stress at the centre of each sub-layer Example of Settlement Calculation The next step is to calculate the initial and final effective stress at the centre of each sub-layer Example of Settlement Calculation • Initial State at A Total stress σ zz = 2x 18 + 3 x 22 + 2 x × 19.06 = 140.12 kPa The next step is to calculate the initial and final effective stress at the centre of each sub-layer Example of Settlement Calculation • Initial State at A Total stress Pore water pressure u w = 5 x 9.8 kPa = 49 kPa (3a) σ zz = 2x 18 + 3 x 22 + 2 x × 19.06 = 140.12 kPa The next step is to calculate the initial and final effective stress at the centre of each sub-layer Example of Settlement Calculation • Initial State at A Total stress Pore water pressure (3a) Effective stress σ′ zz = σ zz - u w = 140.12 - 49 = 91.12 kPa σ zz = 2x 18 + 3 x 22 + 2 x × 19.06 = 140.12 kPa u w = 5 x 9.8 kPa = 49 kPa The next step is to calculate the initial and final effective stress at...
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## This note was uploaded on 08/30/2011 for the course CIVL 2410 taught by Professor Dairey during the Three '11 term at University of Sydney.

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sma09 - Calculation of Settlement H ∆ S z x Settlement of...

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