Wireshark_Ethernet_ARP_Solution_July_22_2007

Wireshark_Ethernet_ARP_Solution_July_22_2007 - Solution to...

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Unformatted text preview: Solution to Wireshark Lab: Ethernet and ARP Fig. 1 GET request Ethernet information 1. What is the 48-bit Ethernet address of your computer? The Ethernet address of my computer is 00:09:5b:61:8e:6d 2. What is the 48-bit destination address in the Ethernet frame? Is this the Ethernet address of gaia.cs.umass.edu? (Hint: the answer is no ). What device has this as its Ethernet address? [Note: this is an important question, and one that students sometimes get wrong. Re-read pages 468469 in the text and make sure you understand the answer here.] The destination address 00:0c:41:45:90:a8 is not the Ethernet address of gaia.cs.umass.edu. It is the address of my Linksys router, which is the link used to get off the subnet. 3. Give the hexadecimal value for the two-byte Frame type field. What do the bit(s) whose value is 1 mean within the flag field? The hex value for the Frame type field is 0x0800. 4. How many bytes from the very start of the Ethernet frame does the ASCII G in GET appear in the Ethernet frame? The ASCII G appears 52 bytes from the start of the ethernet frame. There are 14 B Ethernet frame, and then 20 bytes of IP header followed by 20 bytes of TCP header before the HTTP data is encountered. 5. What is the hexadecimal value of the CRC field in this Ethernet frame? The hex value for the CRC field is 0x 0d0a 0d0a. Fig. 2 OK response Ethernet information 6. What is the value of the Ethernet source address? Is this the address of your computer, or of gaia.cs.umass.edu (Hint: the answer is no ). What device has this as its Ethernet address? as its Ethernet address?...
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Wireshark_Ethernet_ARP_Solution_July_22_2007 - Solution to...

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