# HW3 - Next add the two middle scores and divide by 2(3 4/2...

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Homework 3 Chapter 3: 5, 7, 8, 10, 20 5. The mean, medium, and mode will have the same value when the distribution is symmetrical and has one mode. 7. The mean is not often a good measure of central tendency for a skewed distribution because extreme scores place the mean in the tail, far away from the majority of the scores in the distribution. Therefore, the mean does not represent the central value. 8. Mean = (1+4+3+5+4+2+4+2+5+3)/10 = 3.3 Median = first, list the scores in order: 1 2 2 3 3 4 4 4 5 5
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Unformatted text preview: Next, add the two middle scores and divide by 2: (3+4)/2 = 3.5 Mode = 4 10. Mean = [(5*2) + (4*5) + (3*3) + (2*2) + (1*2)]/14= (10+20+9+4+2)/14 = 45/14 = 3.21 Median = 1 1 2 2 3 3 3 4 4 4 4 4 5 5 (3+4)/2 = 3.5 Mode = 4 20. Sample 1: n 1 = 4, X 1 = 8 X 1 = ∑X 1 / n 1 8 = ∑X 1 / 4 ∑X 1 = 32 Sample 2: n 2 = 6, X 2 = 12 X 2 = ∑X 2 / n 2 12 = ∑X 2 / 6 ∑X 2 = 72 weighted mean = (∑X 1 + ∑X 2 )/ n 1 + n 2 = (32 + 72)/6 + 4 = 10.4...
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## This note was uploaded on 04/05/2008 for the course SOC 390 taught by Professor Lewin during the Fall '07 term at ASU.

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