BUS 308 Week4 hmwk - It is not significant because the...

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7.10 Mean=5.55 Standard Deviation= 9.21 18.42 7.22 a. -2.37 √.2*.8/1000=.012649 b. yes, because -2.37 is less then the p of .2 8.6 b. Yes, both numbers exceed 50lbs c. No, 49.91 falls below the 50lb point d. I'm convinced that this is the best of all of the 30 gal bags; it exceeds 50lbs and the lowest probability 8.38 yes,  I came up with .51, .61 after rounding so yes we can be 95% positive to be higher than .48 12.10 all are 500 P1=.87, P2=.08, P3=.03, P4=.01, P5=.01 E1=435, E2=40, E3=1 4.45+22.5+3.26+1.8+3.2=35.21 B.  I conclude it is the same; the excel is more accurate 12.18a
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Unformatted text preview: It is not significant because the P-value is less then .05 12.4/5 20.6/5 2 =2*9.21 =.020 p=.2 P( .17 if p =.2 P(z.17-.2/.012649) a.95%= 50.12 , 51.03 99%= 49.99, 51.17 95= 50.5751.96*1.65/50.575 = .455 99= 50.575 A. X= 35.21 (479-435)/435 +(10-40)/40 +(8-15)/15 +(2-5) y was 49.91 which still exceeds the others from table 1.9 195/350=.5571 .5051, .6091 (Pk) 15, E4=5, E5=5 F1=479, F2=10, F3=8, F4=2, F5=1 52.575*1.65/50.575=.597 .5571 1.96(.5571*.4429)/350 .5571 .052 /5 +(1-5)/5...
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This note was uploaded on 08/29/2011 for the course BUSINESS 101 taught by Professor All during the Spring '11 term at Ashford University.

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BUS 308 Week4 hmwk - It is not significant because the...

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