BUS 308 week2 - Week2 4.4 A B B BGB G G BBB BBG G B B G BGG...

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Week 2 4.4 A B BBB B G BBG B G B BGB G BGG B GBB G B G GBG G B GGB G GGG First Child Second Child Third Child Boy/ Girl Outcome B GGB + BGG = 1/8 + 1/8 = 2/8 BBG+BGB+GBB = 1/8+1/8+1/8  BBB = 1/8 4.20 Jane(A) .5  John(B) .4  (B|A)=.7 P(A U B)= P(.5)+P(.4) - P(.5)*P( P(A') = 1 - P(A) = 1 - .5 = 0.5. 5.12 A. P(1)=1/15=.07 P(2)=2/15=.13 P(3)=3/15=.2 P(4)=4/15=.27 1 . 1/8 That they will be all boys or all girls 1/4 if your counting both 2.  2/8 = 1/4 3.  3/8 4.  1/8 A.  .55 B.  .5 C.  I would say no as P(A|B) does not equal P(A) or P(B)
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P(5)=5/15 =1/3=.33 B.  P(x) Are all greater than 0 and all values of x add to 1
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This homework help was uploaded on 08/29/2011 for the course BUSINESS 308 taught by Professor Deborahlomas during the Spring '10 term at Ashford University.

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BUS 308 week2 - Week2 4.4 A B B BGB G G BBB BBG G B B G BGG...

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