Bisection Quiz 2

Bisection Quiz 2 - [ 1.225 f (c ) = 1 − e −2 c − 1 =...

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Unformatted text preview: [ 1.225 f (c ) = 1 − e −2 c − 1 = 0 c Bisection!!! xlow 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 xhigh 0.5 1.05 1.05 1.05 1.05 1.08 1.08 1.08 1.08 1.08 1.08 1.08 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 xr 1.6 1.6 1.33 1.19 1.12 1.12 1.1 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 flow 1.05 1.33 1.19 1.12 1.08 1.1 1.09 1.09 1.09 1.09 1.08 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 1.09 fhigh 0.55 0.02 0.02 0.02 0.02 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 f(xr) -0.27 -0.27 -0.14 -0.06 -0.02 -0.02 -0.01 -0.01 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.02 -0.14 -0.06 -0.02 0 -0.01 -0.01 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 ea(%) 20.75 11.58 6.15 3.17 1.56 0.79 0.39 0.2 0.1 0.05 0.02 0.01 0.01 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 et(%) 3.24 22.1 9.43 3.09 0.07 1.51 0.72 0.32 0.12 0.02 0.03 0 0.01 0.01 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 SOLUTION 1.09 ...
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This note was uploaded on 08/31/2011 for the course ENGR 3723 taught by Professor Staff during the Summer '11 term at Oklahoma State.

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