Solution to Assignment 8

Solution to Assignment 8 - SOLUTION TO HOMEWORK #8 13.1 So...

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SOLUTION TO HOMEWORK #8 13.1
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So we get the expression: 22 2 2 1 H pro H pro a iso iso aa y y X K P aX y == = When there is zero products, the equilibrium fraction of isopropyl alcohol is:
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03 . 0 94 . 0 1 225 . 8 2 2 = = = = iso a y X X X K When we have a 50/50 mixture of hydrogen and reactant to begin with, or 0.5mol each, we have: Species In Out Yi iso 0.5 0.5-X (0.5-X)/(1+X) prop 0 X X/(1+X) H2 0.5 0.5+X (0.5+X)/(1+X) total 1+X K a = 8.225 = X (0.5 + X ) 0.5 X () 1 + X = (0.5 X + X 2 ) 0.5 0.5 X X 2 X = 0.9436 y iso = 0.0290 When we have a 50/50 mixture of hydrogen and reactant to begin with, or 1mol each, we have: Species In Out yi iso 1 1-X (1-X)/(2+X) prop 0 X X/(1+X) H2 1 1+X (1+X)/(2+X) total 2+X ( ) 2 2 (1 ) ( ) 8.225 12 2 0.68 0.12 a iso XX X X K PP X X X y ++ == = −+ = =
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Problem 2 We need the following: Now, we know that if ideal and T is constant, we get: 2 2 1 1 2 1 2 1 1 1 2 2 2 1 1 1 2 2 n P n P n V P n V P n V P n V P = = = but, the pressures can be calculated from the equilibrium constant, and since the equilibrium constant is only a function of temperature, the pressures will be the same. Essentially, if the volume is doubled, then the oxalate will decompose more. From equilibrium, we know that:
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CO a P K = And since we know that it is an ideal gas, we have: V RT n P K CO CO a = = Now, we can solve for the number of moles of CO as a function of volume: RT V K n a CO = Now, if the volume is increased after this happens (calcium oxalate fully decomposes), nothing will happen because the equilibrium constant is a function of temperature only. Since we are at constant temperature, the increase in volume would not affect the equilibrium constant. #Problem 3: Write the number of moles of Ca oxalate as a function of V in problem 13.2 and establish the volume at which the Ca oxalate completely decomposed as a function of the initial amount. What happens if the volume is increased after that value?
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Solution to Assignment 8 - SOLUTION TO HOMEWORK #8 13.1 So...

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