Wi09 Exam 2 key0

Wi09 Exam 2 key0 - BICD 100 Genetics Exam 2 February 13,...

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Unformatted text preview: BICD 100 Genetics Exam 2 February 13, 2009 Prof. Soowal Be sure to put all answers on your scantron. No electronics (calculators, phones, MP3 players, etc.) permitted during exam. BICD 100 Exam 2 Page 2 Questions 1‐5. Use the information about the blood types of these 12 individuals to help sort out their confusing personal lives. Females Blood Type Males Blood Type Mary Sue A Billy Bob O Daisy AB Dale B Wilma A Fred AB Cindy Beth B Bubba B Eva Jo AB Junior AB Kandy O Earl O 1. Cindy Beth gave birth to a boy, Ray, whose blood type was B. Which of the men could have been Ray’s father? a. Dale or Bubba b. Fred or Junior c. Dale, Bubba, Fred or Junior d. Billy Bob, Dale, Bubba, and Earl e. Billy Bob, Dale, Fred, Bubba, Junior and Earl 2. Wilma’s child, Norma, was born with blood type O. Which of the following could be the father? a. Dale or Bubba b. Fred or Junior c. Dale, Bubba, Fred or Junior d. Billy Bob, Dale, Bubba, and Earl e. Billy Bob, Dale, Fred, Bubba, Junior and Earl 3. EvaJo had a girl, Martha, whose blood type was AB. Which of the following could not be her father? a. Dale or Bubba b. Fred or Junior c. Dale, Bubba, Fred or Junior d. Billy Bob or Earl e. Billy Bob, Dale, Fred, Bubba, Junior or Earl 4. Mary Sue and Bubba have a child. What possible blood types could their child be? a. A c. O e. Any of b. B d. AB these 5. Which of the following statements is true for Daisy? a. She can receive any blood type. b. She can donate to any blood type. c. She can receive type A, B, and AB but not O. d. She can donate to types A, B, and AB, but not to type O. e. She can only receive from only O. BICD 100 Exam 2 Page 3 6. Which of the following is a true statement: a. People who have the A antigen normally would not produce the anti‐A antibody. b. People who are type AB normally produce both anti‐A and anti B antibodies. c. The only ABO type blood that normally does not have either antigen is AB. d. People who have the A antigen normally would produce the anti‐A antibody. e. People who have the B antigen normally would produce the anti‐B antibody. 7. How many different phenotypes and genotypes can be determined by the three alleles, ABO? a. 6 phenotypes, 6 genotypes b. 4 phenotypes, 4 genotypes c. 3 phenotypes, 6 genotypes d. 4 phenotypes, 6 genotypes e. 6 phenotypes, 4 genotypes Questions 8‐12. Match the following terms to the best description. a. epistasis b. incomplete dominance c. codominance d. reduced penetrance e. lethal alleles 8. The crossing of two heterozygotes gives a ratio of 2:1 E 9. The heterozygote resembles neither homozygote B 10. The alleles of one gene mask the effects of alleles of another gene A 11. Less than 100% of the individuals possess a particular phenotype D 12. Both parental phenotypes are expressed in the F1 hybrids C 13. In Klinefelter’s Syndrome, the individual is: a. XX and phenotypically male b. X0 and phenotypically female c. XXY and phenotypically male d. XXY and phenotypically female e. XXY and phenotypically either male or female 14. Which of the following are true about mosaics? a. They occur in all phenotypic females. b. They occur in both genotypically normal males and females. c. A heterozygote XRXr will express both forms of the gene equally. d. A heterozygote XRXr will preferentially express the dominant allele. e. More than one of the above. BICD 100 Exam 2 Page 4 The Addams’ family of 0001 Cemetery Lane carries an X‐linked recessive trait, Xa, which causes extreme paleness along with black hair. 15. Gomez Addams, the father of this family, is not sure of his genotype. His wife, Morticia, is affected and is homozygous for this gene. Which of the following is a true statement? a. Gomez’s genotype must be XAY, if all of their daughters are affected. b. Gomez’s genotype must be XaY, if all of their daughters are carriers but not affected. c. Gomez’s genotype must be XAY, if all of their daughters are carriers but not affected. d. None of the above is true. e. All of the above are true. 16. In another family (the Muensters) affected with the same gene, you see that all of this family’s children (boys and girls) are affected. What conclusions can you draw? a. The mother (matriarch) must be affected. b. The father (patriarch of the pedigree) must be affected. c. Daughters of this family, even if they mate non‐affected males, will yield affected sons. d. None of the above is possible. e. All of the above are possible. 17. Which of the following statements is true? a. If a trait is X‐linked recessive, an affected male will never have affected sons b. If a trait is X‐linked recessive, an affected female will always have affected sons. c. If a trait is X‐linked dominant, males and females will have exactly the same probability of being affected. d. More than one of the above is true. e. None of the above is true. BICD 100 Exam 2 Page 5 Questions 18‐22. Match the following pedigrees to the most likely form of inheritance. Use each answer once. a. X‐linked dominant b. X‐linked recessive c. Autosomal dominant d. Autosomal recessive e. Y‐linked 18. E 20. C 19. D 21. B 22. A BICD 100 Exam 2 Page 6 Two unlinked genes control weapon choice in ax murderers. Ax murderers who prefer single‐edge axes have been shown to have a dominant allele A, while ax murderers who prefer double‐edge axes are homozygous for the recessive allele a. Handle length choice is also controlled by a single gene, L; the dominant allele, L, causes a preference for long handles, while homozygous ll individuals prefer short‐ handled axes. A true‐breeding murderer who prefers long‐handled, single‐bladed axes is crossed with a true‐breeding murderer who prefers short‐handled, double‐ bladed axes. The offspring are allowed to self‐cross to form an F2. 23. What phenotypes, and in what proportion, do you expect to see in the F2? a. 9 long, single : 3 long, double : 4 short, single b. 9 long, single : 7 short, double c. 1 long, single : 1 long, double : 1 short, single : 1 short, double d. 3 long, single : 1 short, double e. None of the above 24. From the F2 progeny, a murderer who prefers a short‐handled, single‐edged blade is chosen at random. What is the probability that this murderer is homozygous AA? Heterozygous Aa? a. 1/16; 1/2 b. 2/3; 1/3 c. 1/3; 2/3 d. 1/2; 1/4 e. 1/4; 1/2 When Jason Voorhees isn’t busy terrorizing the campers of Camp Crystal Lake or sharpening his weapons, he is an avid Drosophila enthusiast. He bred hundreds of fruit flies but found a few to be especially interesting to him. The following table shows the data he obtained. Unfortunately, Jason is not a geneticist and could not figure out some of the information required to finish his table. You foolishly agree to help him out. Individual # X #Y # Sets of Sex Chromosomes Chromosomes Autosomes 1 2 0 3 2 2 1 Metafemale 3 2 1 5 4 1 1 Male 5 2 1 2 25. What is the sex of individuals 1, 3, and 5? a. Metafemale; Metamale, Female b. Metafemale; Intersex, Male c. Intersex, Intersex, Male d. Intersex, Metamale, Female e. Intersex, Metafemale, Female 26. How many sets of autosomes could individual 2 have? a. 1 b. 2 c. 3 d. 4 e. 5 BICD 100 Exam 2 Page 7 After retiring from the ax murderer trade, Jason Voorhees decided to settle down with one of the former counselors from Camp Crystal Lake. Soon, they had two sons, Freddy and Michael, who begged for some pets. Jason purchased two bunnies with short, spotted hair. The bunnies gave birth to a litter of 160 offspring with the following fur phenotypes: Fur Number Short, spotted 82 Long, spotted 42 Short, solid 29 Long, solid 7 27. What are the genotypes of the original Voorhees bunnies? (Use “A” for the dominant fur length allele and “B” for the dominant fur color allele.) a. AABB and aabb b. AaBB and aaBb c. aaBB and AAbb d. AaBb and AaBb e. None of the above 28. In order to determine if this cross fits the prediction that these are two unlinked genes, Jason decides to perform a χ2 test. How many degrees of freedom are there for this experiment? a. 4 b. 3 c. 2 d. 1 e. 0 29. The χ2 value for this cross is around… [Please approximate the numbers here!] a. 6.5 b. 8 c. 0.25 d. 0.8 e. 3.7 30. Based on your χ2 test, the degrees of freedom, and the chart on the next page, what can you conclude about the progeny resulting from the Voorhees bunny mating? a. The data suggests that we should reject the hypothesis that the outcome is due solely to random chance b. The data suggests that we fail to be able to reject the hypothesis that the outcome is due solely to random chance c. We have inadequate amounts of data to make such a conclusion d. The data suggests that we should accept the hypothesis that the outcome is due solely to random chance e. None of the above BICD 100 Exam 2 Page 8 ...
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This note was uploaded on 09/01/2011 for the course BICD 100 taught by Professor Nehring during the Winter '08 term at UCSD.

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