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Spring 07 HW 6 SOlutions

# Spring 07 HW 6 SOlutions - Problem 6-4 Temperature = 528 R...

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Problem 6-4 Temperature = 528 R, Pressure = 1000psia, V= 3.2cu ft, Z = 0.89 , , 0.89 528 0.02827 0.02827 0.01328 1000 3.2 240.9 0.01328 g g T P T P g sc sc g ZT B B P V V B V cu ft V B × = = × = = = = = Therefore, the standard cubic feet in the cylinder is 240.9 Alternative solution: 10.2 0.6359 16.04 / m lbmass n lbmol M lbmass lbmol = = = From Avegadro’s law: V sc = n*379.4 = 241.26 scf Problem 6-8 A = 40 acres = 27878400 ft 2 , h = 21 ft , Φ = 0.18 , S w = 0.33, Z = 0.951 from example 3-10 43560 (1 ) wi g Ah S G B φ × - = Where, 3 0.0282 0.951 (194 460) 0.0282 0.0046 3810 g Z T ft B P scf × × × + = = = 10 43560 (1 ) 27878400 21 0.18 (1 0.33) 1.53 10 0.0046 w g Ah S G scf B φ × - × × × - = = = ×

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Problem 6-9 T pc = 350.17 R and P pc = 666.9 psia From example 3-10 194 460 1.87 350.17 5000 14.7 7.522 666.9 pr pc pr pc T T T P P P + = = = + = = = From fig. 3-7 Z = 1.05 3 0.0282 1.05 (194 460) 0.0282 0.00386 5000 14.7 g Z T res ft B P scf × × × + = = = + Problem 6-12 D = 5.761 in, P = 1000 psia, q = 2.4 MMscfd, T = 100 F, Assumptions: Heptanes plus has the same properties of n-Heptane Component mol. Percent Tc R yiTci Pc psia yiPci Hydrogen sulfide 0 672.4 0 1300 0 Carbon dioxide 1.67 547.9 9.2 1071 17.9 Nitrogen 0.32 227.5 0.7 493 1.6 Methane 71.08 343.3 244 666.4 473.7 Ethane 15.52 549.9 85.3 706.5 109.6 Propane 7.36 666.1 49.0 616 45.3 i-Butane 0.92 734.5 6.8 527.9 4.9 n-Butane 1.98 765.6 15.2 550.6 10.9 i-Pentane 0.33 829.1 2.7 490.4 1.6 n-Pentane 0.26 845.8 2.2 488.6 1.3
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Spring 07 HW 6 SOlutions - Problem 6-4 Temperature = 528 R...

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