MOTIONOFACENTEROFMASS

MOTIONOFACENTEROFMASS - MOTION OF A CENTER OF MASS Consider...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
MOTION OF A CENTER OF MASS Consider a system of particles where the position of the CM is given by: Taking the derivative wrt time gives: 11 ii cm i cm i i i th i cm i i i sys mr dr d dt dt M dr v m m v M dt M v velocity of i particle Mv m v p P sys cm P Mv Total Linear Momentum of a System 1. The total linear momentum of the system is equal to the total mass of the system times the velocity of the center of mass of the system. 2. The total linear momentum of the system is equal to that of a single particle of mass M located at the center of mass and moving with a velocity equal to that of the center of mass. cm r M
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Background image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Page1 / 3

MOTIONOFACENTEROFMASS - MOTION OF A CENTER OF MASS Consider...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online