ex7_2 - k5=3.98e9; k2=2.3e6; k4=9.53e8; k

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% "ex7_2" % m-file to solve example 7.2 % % x(1)=Cp1 % x(2)=Cp5 % xdot(1)=dCp1/dt, xdot(2)=Cp5/dt % function xdot=ex7_2(t,x) f k1=1.5e-3; k3=5.71e4;
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Unformatted text preview: k5=3.98e9; k2=2.3e6; k4=9.53e8; k xdot(1,:)=-((3*k1*x(1))+k3*(2*k1/k5)^.5*x(1)^0.5); xdot(2,:)=k3*(2*k1/k5)^.5*x(1)^.5;...
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This note was uploaded on 09/02/2011 for the course CHEM 102 taught by Professor Kmn during the Spring '11 term at Babson College.

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