Lecture 4 Post

# Lecture 4 Post - Lecture 4 Monday 29 August 2011 Chapter 2:...

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Unformatted text preview: Lecture 4 Monday 29 August 2011 Chapter 2: Motion along a Straight Line (along the x-axis) Instantaneous position x ( t ), velocity v x ( t ), acceleration a x ( t )-- Obtain v x ( t ) and a x ( t ) by differentiating x ( t ) and v x ( t ) with respect to t , respectively Distance D traveled , average speed v av , average velocity v av x , and average acceleration a av x v x ( t ) and x ( t ) obtained by integrating a x ( t ) and v x ( t ) with respect to t , respectively At what time(s) is the velocity v x zero? 1.-1 s and +1 s 2. 0 s only 3.-2 s and +2 s only 4.-2 s, 0 s, and +2 s-1.5-1.0-0.5 0.0 0.5 1.0 1.5-2-1 1 2 x (m) t (s) Question Solution The velocity v x is zero when the slope dx dt is zero, which happens at times t = ! 2 s, 0 s, and +2 s . ! A particle is moving along the x- axis with the following position x versus time t : During what time interval(s) is the velocity v x negative?...
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## This note was uploaded on 09/05/2011 for the course PHYS 221 taught by Professor Herrera-siklody during the Spring '08 term at Iowa State.

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Lecture 4 Post - Lecture 4 Monday 29 August 2011 Chapter 2:...

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