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1-26-EquipotentialSurfacesBB

1-26-EquipotentialSurfacesBB - Electric Potential of a...

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+ r kq V = Source charge q E field line High V low V Example V m C C m N V A 300 2 . 1 ) 10 0 . 4 )( / 10 9 ( 8 2 2 9 + = × + × = - C q 8 10 0 . 4 - × + = m r A 2 . 1 = m r B 0 . 3 = V m C C m N V B 120 0 . 3 ) 10 0 . 4 )( / 10 9 ( 8 2 2 9 + = × + × = - Electric Potential of a Point Charge E field line - - q +q C q 8 10 0 . 4 - × - = V m C C m N V A 300 2 . 1 ) 10 0 . 4 )( / 10 9 ( 8 2 2 9 - = × - × = - V m C C m N V B 120 0 . 3 ) 10 0 . 4 )( / 10 9 ( 8 2 2 9 - = × - × = - High V low V (derivation is skipped.) +300V +120V -300V -120V
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Electric Potential: multiple point charges Total electric potential at point P = algebraic sum of individual potentials V d kq r kq V 1872 2 2 2 + = = = V d kq d q k r kq V 1872 ) ( 3 3 3 - = - = - = = 1 2 4 3 + + - - V m C C m N d kq r kq V 936 ) 96 . 0 ( 2 ) 10 0 . 2 )( / 10 99 . 8 ( 2 6 2 2 9 1 1 1 + = × + × = = = - V d kq d q k r kq V 1872 ) ( 4 4 4 - = - = - = = 4 3 2 1 V V V V V TotalAtP + + + = d = 0.96m q = 2.0μC r kq V = ) 1872 ( ) 1872 ( 1872 936 V V V V - + - + + + = V 936 - =
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Example 20-4 Fly Away q 1 q 2 q 3 q 1 and q 2 are fixed. q 3 is free to move . (a) Find the electric potential due to q 1 and q 2 at the initial location of q 3 (top corner of the triangle).
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