Exam 1-solutions-2 - Version 284 Exam 1 mccord (51600) 1...

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Unformatted text preview: Version 284 Exam 1 mccord (51600) 1 This print-out should have 34 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points How many electrons can possess this set of quantum numbers: principal quantum num- ber n = 4, angular quantum number = 2? 1. 14 2. 2 3. 18 4. 16 5. 6. 4 7. 12 8. 10 correct 9. 8 10. 6 Explanation: Use the rules for the quantum numbers: If n = 4 and = 2 ( i.e. , 4 d ), then m =- 2 ,- 1 , , +1 , +2 are permitted; there are five different orbitals and m s = 1 2 , each holding two electrons. 002 10.0 points What is the maximum value that m can have for a 3 d orbital? 1.- 1 2.- 3 3.- 2 4. 3 5. 6. 2 correct Explanation: m =- , ..., , ..., For a d orbital = 2 . 003 10.0 points A given atomic orbital has a total of two nodal planes. What type of orbital is this? 1. d correct 2. g 3. s 4. p 5. f Explanation: A node is a point, a plane or a three dimen- sional region of space where the sign of the wavefunction changes from positive to neg- ative (or negative to positive), so it equals zero. The lowest energy orbital of each type will have no three dimensional nodes but dif- fering numbers of nodal planes: 1 s no nodal planes 2 p one nodal plane (two opposing lobes of different signs) 3 d two nodal planes (four opposing lobes of two different signs) 4 f three nodal planes (six opposing lobes of two different signs) (One orbital has only one nodal plane and one conical node for both 3 d and 4 f .) If we go to the next higher value of n for the same type of orbital we would add a spherical (radial) node but the number of nodal planes would remain the same. 004 10.0 points How many electrons can possess this set of quantum numbers: principal quantum number n = 4, magnetic quantum number m =- 1? Version 284 Exam 1 mccord (51600) 2 1. 2 2. 10 3. 18 4. 5. 16 6. 8 7. 6 correct 8. 12 9. 4 10. 14 Explanation: Use the rules for the quantum numbers: If n = 4 then = 0 , 1 , 2 , 3; however, for m =- 1, = 1 , 2 , 3. Each of these permit- ted sets of values of n , and m specifies ONE orbital: n = 4, = 1, m =- 1: 4 p n = 4, = 2, m =- 1: 4 d n = 4, = 3, m =- 1: 4 f and each orbital can have m s = 1 2 ; i.e. , can hold two electrons. 005 10.0 points How many V( r ) terms are found in the solution to the Schr odinger equation for a Li + ion? 1. 1 V( r ) terms 2. 4 V( r ) terms 3. 3 V( r ) terms correct 4. 5 V( r ) terms 5. 2 V( r ) terms 6. 6 V( r ) terms Explanation: Each of the two electrons has an attrac- tive potential energy term with the nucleus. And they mutually repel each other in a final potential energy term. 006 10.0 points In a one-dimensional particle in a box, for n = 6, how many wavelengths equals the size of the box?...
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Exam 1-solutions-2 - Version 284 Exam 1 mccord (51600) 1...

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