2300HW07 - ECE 2300 CIRCUIT ANALYSIS HOMEWORK #7 1) The...

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ECE 2300 – CIRCUIT ANALYSIS HOMEWORK #7 1) The current i C (t) through the capacitor in Figure 1 is given by the plot shown in Figure 2. It is given that v C (2[ms]) = 6[V]. Find v C (8[ms]). v C (t) - + 150[pF] i C (t) Figure 1 i C (t) , [ μ A] t,[ms] 3 -3 3 6 9 12 Figure 2 2) In the circuit shown below, the switched closed at t = 0. No energy was stored in the capacitor, and no energy was stored in the inductor, at t = 0. The expression for v S (t) is given below. Find the power delivered by the voltage source at t = 5[s]. 2 2 V ( ) 6 ; for 0. s S v t t t = 600[H] + - v S (t) 4.7[k ] t = 0 1[mF] 2.2[k ] 7.1
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3) In the circuit shown below, the two switches were open for a long time before t = 0, until all voltages and currents stopped changing. Then, both switches closed at t = 0. Then, switch SWA opened again 2[ μ s] later. a) Find i Q (0 - ). b) Find i X (0 - ). c) Find i Q (0 + ). d) Find i X (0 + ). i X 3.3[k ] 4 i X + - 7[V] 4.7[k ] L 1 = 3[mH] t = 0 Switch SWA t = 0 2.2[k ] Switch SWB t = 2[ μ s] i Q 4) In the circuit shown below, switches SW1 and SW2 have been closed for a long time before t = 0, allowing all voltages and currents to stop changing. At t = 0, switch SW1 opens and remains open. At
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2300HW07 - ECE 2300 CIRCUIT ANALYSIS HOMEWORK #7 1) The...

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