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Unformatted text preview: —_ Physics 116B — Exam #3 (Wednesday) — Fall 2008 i Only calculators and pens/pencils are allowed on your desk. No cell phones, music
players, or additional scrap paper. You have 75 minutes to complete the exam. Name Section (Circle): 3 Helms TR 8:109:25
1 Helms TR 11:0012:15
If you are in Prof. J ohns’s class, you’re in the wrong room! I pledge my honor that I have neither givennor received aid on this work. Signed MC Prob 9 Raw Score Percentage % MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question, Figure 29.1
{—— 20 cm —> 10:) e5: 1) In Fig. 29.1, a wire and a 10—0 resistor are used to form a circuit in the shape of a square, 20 cm by 1)
20 cm. A uniform but nonsteady magnetic field is directed into the plane of the circuit. The
magnitude of the magnetic ﬁeld is decreased from 1.50 T to 0.50 T in a time intervai of 32 ms. The
average induced current and its direction through the resistor, in this time intervai, are closest to: A) 75 mA, from a to b
B) 75 mA, from b to a
C) 190 mA, from a to b 30 mA, from b to a E) 130 mA, from a to b at: '7 £325;
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r '8’" cf: ‘f :1: r? 1051, is m aims QM vs aifrmms min in Page A/L‘E’“ iix/ Ewe]; law] Mailing] Curm’i @993th Chang,” if) (LL Pmaiuurs ﬂA m3“;  Figure 29.8 a b 2) In Fig. 29.8, the inner loop carries a currentI that is increasing. The resistorR is in the outer loop. 2) The induced current through the resistorR is: ' I A) zero @from a to b C) from b to a hair“! mended“ Tbrooiuws a (plaid “mejr :3 {mowing Miro H4 [362%, TL
OVAL—s (qrmeAr Mus—V produvc. A, Qtiﬂz‘
VYL‘R [5 govt o g ’HAL Fag/.27, A2 Figure 30.1c 219 51H shown. Initially, the switch is open, and there is no magnetic ﬂux in the inductor. At tirnet = f} s, the
switch is closed. In Fig. 30.1c, when the resistor voltage is equal to the inductor voltage, the current
in the circuit is closest to: @AA 8) 0.57A C) 0.86A D) 1.7A E) u A
v 6V
If 0 " Loo ewlt f 2‘}: 35: L g
. = 60V ! i m : m CNN/vi} in. ‘i’LL féﬁéL’léf .K‘S 2V (1, V "ls/LL CUFW‘!" m 444. LJLLoiL cr‘raMJ: :e T O Figure 30.3 10.0 $1 30.0 (I! 3) An R—L circuit has a 60V battery, a 51—H inductor, a 21—0 resistor, and a switch S, in series, as 3) H 4) In Fig. 30.3, the instant after closing the switch, the current through the 60.C—Q resistor is closest to: 4) pl @313 A B) 0.00 A C) 2.50 A D) 3.33 A s) 10.0 A ermine dongs 30$th 44¢
\‘nduclcrs lock le'iﬂf'opm gawk W‘HA {to CLUTet/bl’ 1‘“ 'HJLM. i :x 5;;
et WM 1 (00¢ H (40“me A3 Figure 30.5 75.9 D 290.0 V 35,0 HF 25.0 £1 5) In Fig. 30.5, the potential drop across the 70.0 pF capacitor after the switch has been closed for a
very long time is closest to: A) 101 V 33 V
pl'l) 5i long) alarm.)
“’l‘dlﬂﬁ. Qa‘fcml looks ll l? e i 200v C) 200.0 V D) 0.00 V E) 80.0 V 25% Figure 31.121
X0 = 790 o _ R=500f1 XL: 270 o 6) The 60—Hz ac source of a series circuit has a voltage amplitude of 120 V. The capacitive and
inductive reactances are 790 Q and 270 Q, respectively. The resistance is 500 Q. In Fig. 31.1a, the
capacitance, in pF, is closest to: A) 20 .4 C) 9.7 D) 13 E) 6.5
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KﬁrCta.) F C218:
“(9
“’1” c "M z 3.1%“) IF: 34w: SE : ISBV’ 6)B 7) If the voltage amplitude across an 8.50—pF capacitor is equal to 32.0 V when the current amplitude 7)
through it is 3.33 mA, the frequency is closest to: A) 32.6 Hz .20 MHz C) 32.6 kHz D) 5.20 kHz E)32.6MHz
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sew 3%Egmmwww .zszmoHZ: 520%? F h
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9 8) An L—RC series circuit consists of an 85.0—0 resistor, a 14.0 HF capacitor, a 1.50mH inductor, and 8)
a variable frequency ac source of voltage amplitude 13.25 V. The angular frequency at which the
inductive reactance wili be 4.00 times as large as the capacitive reactance is closest to: A) 2.20 x 103 rad/s @38 x 104 rad/s C) 6.90 x 103 rad/s
D) 3.45 x 103 rad/s
E) 1.10 x 103 rad/s VL’JHXC
Lm=q W CL.) A5 _JE_ Physics 116B — Exam #3 (Thursday) — Fall 2008 Only calculators and pens/pencils are allowed on your desk. No cell phones, music
players, or additional scrap paper. You have 75 minutes to complete the exam. Name Section (Circle): 3 Helms TR 8:109:25
1 Helms TR 11:0012:15
If you are in Prof. Johns’s class, you’re in the wrong room! I pledge my honor that I have neither given nor received aid on this work. Signed MC Prob 9 Raw Total Percentage %
MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Figure 29.9 1) In Fig. 29.9, a bar magnet moves away from the solenoid. The induced current through the resisto; 1) B
R is: A) zero rorn a to b C) from b to a ﬂs Masmi” i3 PwuiA gauche/J H €le Musi‘ [QM—36km}: a mat“ NAIL ‘R'ﬁlol ( ‘
a“,
d§;;:::) niwwdt 9' 2) A small square coil is located inside an ideal solenoid at the center with its plane oriented 2)
perpendicular to the axis of the solenoid. The resistance of this coil is 200 Q and each side is 4.00 I cm long. The solenoid has 125 windings per centimeter of length. If the current in the solenoid is increasing at a constant rate of 1.50 A/s, the current in the square coil is: A) decreasing at 1.50 A/s B) initially equal at 18.8 uA but is increasing ::::S:i:t81:: AIS gufl‘ {Q Vow Mud” “in C6! lmlaLﬁ Ill
: E)zero J .. EE’ZQGQ a ﬂ fies?“ré”sat an“) Ra‘s «L (Ll/16m 15 win
g ﬁgﬁﬁgﬁvna Eisnﬂxgenn: y
l ' antitaper men I ‘flﬁ 5: :‘ET ﬂ 5g ’5 C ” OF re W "at" ‘ ‘9 509 a? is (onsisci’) 5° : “" (‘Olmvwmollgxgr X F >
25L 8 is. consdmwfl: so
’HILL aqua/A” l’f\ 2'1?.g*/LA gigxmg gas? :5 Kong‘lﬁﬂ'l": Al D 1’: H»; mix) answer, Figure 30.1d 250 3) An R—L circuit has a 60—V battery, a 45—H inductor, a 250 resistor, and a switch S, in series, as 3) E
shown. Initially, the switch is open, and there is no magnetic flux in the inductor. At timet = 0 s, the
switch is closed. In Fig. 30.101, the rate of change of the current when the current is 1.5 A is closest to:
A) 0.67 A/s B) 0.83 A/s C) 0.75 A/s D) 0.58 A/s @150 A/s
I/é:) = 1:, 0 ~65”) I. SA 42W) vise/s) 3.4.3:... E, Jr):
; jf a; V 3; (99V ,3 LA 1.2:); see/rt 0:“ 
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R 26:51 lgs e [@7/ 2:4 .345 tgﬁ 6"
td 1':
. E=ﬁ4(37s) O'SC‘A
) so : warmtssﬂﬁms Figure30.3 10.0 0 30.0 0 r 15.0
1000‘)? “‘H 4) In Fig. 30.3, after the switch has been closed and left closed for a very long time, the potential drop 4) A
across the 600!) resistor is ciosest to: @000 V B) 85.7 V C) 66.7 V D) 100.0 V E) 90.0 v Witr a lens 05M, 44¢ LiamH {noiuc or acid
hire a sitar—F “£5955 “i'kt, (60.31. rescsvtor. Wage,
0° Curr'evfjr Mow; ibvmsh J/LA» crazier and W
Pcicvriccd Gimp amass P3? )5 grav Figure 30.5
75.0 {2 200.0V . 35,0 PF 25.0 D 5) In Fig. 30.5, the potenﬁa drop across the 15.0—mH inductor just after closing the switch is closest to:
A) 0.00 V 50.0 V C) 50.0 V D) 200.0 V E) 100.0 V [mien/)9} m cqpqaiﬂfj $0.4" Séar'zs‘ arm/ Ihdwca/vrﬁ /ooé 01:93“ Cr‘rem'JS. W..W..WM/ww
V“WV“ Wit
% «r» ;
LWJMAM V fﬁ JM§+ 5;"‘59 Citrbﬁﬁ 4154... P6§P¢g¥af , \J 20:20
“:Ww. . ‘2: 2 A
594% Mac.) r71. A8 5) .3. Figure 31.1b
XC = 710 o R=4900 6) The 60Hz ac source of a series circuit has a voltage amplitude of 120 V. The capacitive and
inductive reactances are 710 Q and 320 Q, respectively. The resistance is 490 D. In Fig. 31.1b, the
inductance, in mH, is closest to: A) 1900 C) 3200 D) 4000 s) 5300
XuﬁLW
“My”? “page 01;?st 7) The inductor in a radio receiver carries a current of amplitude 200 mA when a voltage of amplitude 2.4 V is across it at a frequency of 1400 kHz. What ithhe value of the inductance? H
pk.
A) 1.97 ;H B) 1.43 «1H C) 4.42 mH D) 9.20 saH E) 1.36 pH Wm; if LL00 6) 7)_______ 8) A series L—R—C circuit consists of a 175—0 resistor, a 10.0—mII inductor, a 2.50—uF capacitor, and an 8) ac source of amplitude 15.0 V and variable frequency. If the voltage source is set to 3.00 times the resonance frequency, the impedance of this circuit is closest to: @243 Q B) 386 Q C) 525 o D) 344 o E) 175 o (c) Calculate the magnetic force on the slide wire. W Faxes: Saw
“7%” 2 2
(d) From your last answer, show that the velocity of the slide wire as a function of time is given by v(t) 2 v0 e“B_mii“. (4) 22 iﬂaz‘z
i FEWmdﬁwqgge"E LV ﬂAw" E>Lf Git Q MR
_ 1 aien'i 44%, \I'” H. “The infra; (v: V” a“ % 4:)
1% la gFggﬁi’itr éﬁtfééfLIGQ
(A5; V. Qh/x gig: at: “ .22? V V t‘ 9“! I TL? RT “‘2 “‘ Es. ate: «it? m g (e) Calculate the total distance traveled by the slide wire from the point where it was released. a4 a9
= _. “E11 (4)
Ax [we V”§€ m at
0
_M€ ﬂgﬂl
.2» V; at e I
I
I
l
! FREE RESPONSE. Write your ﬁnal answer for each part in the box provided. Partiai credit will only be given if you
show your work and it is clear. 9) A rectangular loop with width L and a slide wire with mass m are shown in the ﬁgure below. A uniform magnetic
field B is directed perpendicular to the plane of the loop, into the page. The slide wire is given an initial speed 00
and then released. The resistance of the loop is negligible and the resistance of the slide wire is R. There is no friction
between the loop and the siide wire. X X X X X X X X X X X X X away.) 9: an abssex Em he. wait? it new. Womb (a) Calculate the magnitude of the emf induced in the loop enclosed by the ﬁxed wire and the slide wire. (Your
answer should depend on v). i 013:
lgli Egg: £84): BEE:31“ ELV 5(v)= BLV (4) (b) Calculate the current in the loop and indicate its direction. f“ E: “a BLV R “ a“
ﬂank; “Emit?! {35>th this Hrs and nil/LL Max is immersing) Lit42:3 law
Stu/s ‘I’LL t‘hdhreﬁp ganged?“ @roduws
a W we deem w ems; e. Riel M oil HM FQSMQ. ‘ ...
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This note was uploaded on 09/05/2011 for the course PHYS 116b taught by Professor Haglund during the Spring '07 term at Vanderbilt.
 Spring '07
 Haglund
 Physics

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