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Unformatted text preview: = ±( ) ( )…. . x 3 32 41 2 2 1 substituting the values Taking the discriminant of =  = …… 32 412 9 8 1 2 possible real number solutions and two…. x intercepts Finishing out the equation = ±( ) ( )= ± x 3 32 41 2 2 1 3 12 = ± = 3 12 =  …. , , , x 1 or 2 which means the x intercepts would be 1 0 2 0if the check is true If the value of , b2 4ac is a negative number then the solution is two , , complex numbers which are not real numbers and no x intercept Example: let’s say a=1,b=2,c=3 = ±( ) ( )…. x 2 22 41 3 2 1 substituting the values The discriminant is = = ……22 413 4 12 8 there is no x intercept and the answer is complex Finishing out the equation… = ±= ± = ± x 2 82 2 2i22 1 i2 =  x 1 i2 or =  + x 1 i2...
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This note was uploaded on 09/05/2011 for the course ECON 101 taught by Professor Smith during the Spring '11 term at University of Phoenix.
 Spring '11
 SMITH

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