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MATH 3360 – Applicable Algebra. HW 11 Solutions
(1) Problem 13 on page 162.
Solution:
Consider
C
=
(
x
,
y
,
z
,
a
,
b
,
c
,
d
)
T
. Then
x
y
z
a
b
c
d
=
1 1 0 1
1 0 1 1
0 1 1 1
1 0 0 0
0 1 0 0
0 0 1 0
0 0 0 1
a
b
c
d
.
From here, you see that
G
0
=
P

I
.
(2) Problem 2.3.
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This note was uploaded on 09/05/2011 for the course MATH 3360 taught by Professor Billera during the Spring '08 term at Cornell University (Engineering School).
 Spring '08
 BILLERA
 Algebra

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