Week 4 Solutions.jspa

# Week 4 Solutions.jspa - Week 4 Homework C HAPTER 8 S...

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Unformatted text preview: Week 4 Homework C HAPTER 8 S AMPLING M ETHODS AND THE C ENTRAL L IMIT T HEOREM 6 page 262 6. a. Sample Values Sum Mean 1 2,2 4 2 2 2,4 6 3 3 2,4 6 3 4 2,8 10 5 5 2,4 6 3 6 2,4 6 3 7 2,8 10 5 8 4,4 8 4 9 4,8 12 6 10 4,8 12 6 b. =(2 + 2 + 4 + 4 + 8)/5 = 4 X = + + + + + + + + + = ( ) / 2 3 3 5 3 3 5 4 6 6 10 4 c. They are equal. The dispersion for the population is greater than that for the sample means. The population varies from 2 to 8, whereas the sample means only vary from 2 to 6. #18 page 274 a. No assumptions are necessary. b. 80 12.649 40 x s = = c. z = 320 330 0.79 80/ 40- = - So probability is 0.7852, found by 0.2852 + 0.5000. d. z = 350 330 1.58 80/ 40- = So probability is 0.7281, found by 0.2852 + 0.4429. e. 0.0571, found by 0.5000 - 0.4429. Chapter 8 C HAPTER 9 E STIMATION AND CONFIDENCE I NTERVALS #4,7 on page 290 Look up .425 in the body of the table. z = 1.44 a. 8.60 gallons b. 7.83 and 9.37, found by 8 60 2 58 2 30 60 . . ( . / ) c. If 100 such intervals were determined, the population mean would be included in about 99 intervals....
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## This note was uploaded on 09/06/2011 for the course FIN n/a taught by Professor N/a during the Spring '06 term at University of Phoenix.

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Week 4 Solutions.jspa - Week 4 Homework C HAPTER 8 S...

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