This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: 4 e − t + 12 1 2. (10 points) Determine mathematically and also sketch the step response for part (c) above (i.e., f nd y ( t ) given r ( t ) is a step input) where F ( s ) = Y ( s ) R ( s ) = 1 ( s + 1)( s + 2)( s + 3) . Y ( s ) = 1 s ( s + 1)( s + 2)( s + 3) . , Is Laplace transform of 1 2 e − 2 t − 1 2 e − t − 1 6 e − 3 t + 1 6 5 3.75 2.5 1.25 0.25 0.2 0.15 0.1 0.05 x y 3. (10 points) Apply the IVT and FVT to question 2 to check that your sketch and answer makes sense. IV T → lim t → y ( t ) = lim s →∞ sY ( t ) = s s ( s + 1)( s + 2)( s + 3) = 1 ∞ = 0 FV T → lim t →∞ y ( t ) = lim s → sY ( t ) = s s ( s + 1)( s + 2)( s + 3) = 1 6 2...
View
Full Document
 Fall '07
 Dixon
 Laplace, Partial fractions in complex analysis, 2 g

Click to edit the document details