eml 3100 integration no. 2

eml 3100 integration no. 2 - Thermodynamics Fuel In...

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1 Thermodynamics Fuel In Turbine output Compressor Heat rejection ? kW output Generator Effic = 90% Elec. Generator Abs. Chiller COP = 0.6 r p = 20 What electrical output from this system could we expect? CHWR 55 deg F CHWS 45 deg F CHW Pump Evaporator Heat Exchanger 8,000 cfm from 75degF, 50% rh to 55deg F db and 53 degF wb Size schedule 40 steel chw pipe Find BHp of pump if there is 200 developed feet of chw piping, 10 ft head loss for the coil, 8 ft head loss for the control valve and 14 ft of head loss for the evap. heat exchanger. Assume the pump effic. = 0.7
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2 Thermodynamics Assumptions for microturbine: assume ideal Brayton cycle with cold air standard assumptions. Assumptions for absorption chiller: assume no losses in the heat transfer from the turbine to the absorption unit. Strategy: Use pressure ratio to get microturbine efficiency. Finding cooling requirement from psyc. analysis of the cooling coil and the COP for the absorption chiller, find the required heat input to the absorption chiller. With the heat input and the turbine efficiency find the turbine output and then the generator input. Effic of ideal gas turbine with cold air standard assumptions = 1 – 1/ (r p (k-1)/k )= 0.575 The psyc analysis of the coil indicates a cooling capacity requirement of 18.6 tons or 223,147 btu/h. Note that you could also calculate the cooling requirement with the equation: Q cooling = cfm * 4.5 *
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This note was uploaded on 09/05/2011 for the course EML 3100 taught by Professor Sherif during the Summer '08 term at University of Florida.

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eml 3100 integration no. 2 - Thermodynamics Fuel In...

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