Test 3 Summer 05 - _“‘—l———un—_—_F Test 3...

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Unformatted text preview: -_“‘—l———un—_._—_._F Test # 3 EEL 3111C Summer 21305 Dr- Srivastava $3.31.".L'EIJ’5KE‘ ............................ __# ......... __ First Name Last Name Section # (1) Consider the following elreuit: ID {in} Find the expressienier frequeneyfg at which E“! is purely resistive. I Lu L R L W C.— R‘ .+. N [3} Consider the circuit shown where the source provides AC power to two leads. Load A: 30 kW @ lagging pfof 0.95; Load B: 15 k‘v’fiR @ lagging pf of 1190. Determine the followine: ‘10 {a} The impedance of lead A. U E = flfifw-Elaea; acetate Llama twirl I: were: a _ b Ea ‘5‘: alga“! LIBJGIST:(3_.40 gr.) I. m aha [ A it - = '13l.£4+-t‘8.1mfl - z: WE amaéfi i. _ : 10 lb} The RMS current phascra ll and I}, :r : tam Artrrffi .f'\_.. a I’VE, ‘— nii (l G-la—JUJ) —+ 2.493 : $533 \l D Eh go revere 2 were? = 13311.3 42am _ z u _ a 3‘ “fig (5.... can VB stamina 2, to o Ania“? ’3‘ 10 {c} The overall power factor seen by the load. Ct "M. ma- * I_ I" Is'e‘Iu-rll: 4-55.34 mm D. U T; 2 Ré‘SvE‘pvfirllalt (0.1+Jcr.l}+;2§'gul}3fi_gqg 5 :: Sloth“; Lé.630V fl Pf; = Gee (4..e32'+21,1f’) : (“cans-ea :aaoa were) lfl (d) The capacitance needed to correct the overall power factor to unity. 1 A5", = @55-3}1(9*H—J04)+ 3151M 413.2.”4- (131$) (gnaw) it + "56“ “HEEL! 2 caaoafleeaee Wt EFFr‘Ef-t C 2 " G2 = M.— : t-a‘a‘mp w.— W we were?“ ...
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