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Unformatted text preview: Residue at z=3i: Residue at z=2i: 3) Using the same contour as before As R approaches infinity the last integral approaches zero, hence There is a simple pole at z = 2+i with residue Hence 4) The first pair of integrals on the right hand side sum to zero (odd function) and the last integral approaches zero as R approaches infinity. As (residue at the simple pole at z = 0). The residue at z = 0 is 1. Therefore...
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 Spring '08
 MEI
 Calculus, Derivative, Methods of contour integration, Pole

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