cpp2_code_f07 - USERNAME NAME_E2 1(15 pts This refers to...

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USERNAME ___________________ NAME ________________________________E2 1.(15 pts) This refers to pro6. Add a new method called Perpendicular2D() to the Vector class. Here is an example. Vector v1(1,1,0); Vector v2; v2 = v1.Perpendicular2D(); This method returns a vector that is perpendicular to vector v1. We will only consider the 2-dimensional case (z-component is 0). If v1 was 3- dimensional, then the method would return a zero vector (all components are zero). For the sake of simplicity, we will assume that the calling vector (v1 in the above example) is on the first quadrant ( 0 , 0 > y x ). To find the perpendicular vector: rotate the original vector 90 0 in counter-clockwise direction, as shown in the figure. Hint: In your solution, you can use the constructor that takes a magnitude and an angle as arguments. Sample Run: Vector v1(1,1,0), v3(1,1,2); Vector v2; v2 = v1.Perpendicular2D(); // v2 will be ( -1, 1, 0) v2 = v3.Perpendicular2D(); // v2 will be (0,0,0) --------------------------------------------- Your Solution -------------------------------------------- Vector Vector::Perpendicular2D(){ Vector zero; if( z != 0){ return zero; } double mag = sqrt(x*x + y*y); double ang = (atan(y/x)/PI)*180 + 90; Vector per(mag,ang); // Or replace these 3 lines with: Vector per( -y, x, 0); return per; }
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