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EML2322L  MAE Design and Manufacturing Laboratory
Useful Motor/Torque Equations for EML2322L
Force
(N)
F = m x a
m = mass (kg)
a = acceleration (m/sec
2
)
Motor Torque
(Nm)
T = F x d
F = force (N)
d = moment arm (m)
Power (W)
P = I x V
I = current (amps)
V = voltage (V)
P = T x
ω
T = torque (Nm)
ω
= angular velocity (rad/sec)
Unit Conversions
Length:
1 in = 0.0254 m
Velocity:
1 RPM = 0.11 rad/sec
Torque:
1 inlb = 0.11 Nm
Power:
1 HP = 745.7 W = 550 lbft/sec
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View Full Document Example 1
Determine if the following motor can be used to lift a 5kg load using a 0.5m lever
arm.
MerkleKorff Gearmotor specifications
Stall Torque = 40 lbin
Stall Current = 3.5 amps
Solution
Convert stall torque from inlb to Nm:
1 inlb = 0.112985 Nm
40 inlb = 40 x 0.112985 Nm = 4.5194 Nm
Calculate the force required to lift the 5kg load:
F = m x a = 5 kg x 9.81 m/s
2
= 49.05 N
Calculate the torque required to lift the force with the lever arm:
We cannot perform the lift with this setup, because the stall torque is smaller than
the torque required for the lift.
We must either shorten the length of the lever arm,
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This note was uploaded on 09/05/2011 for the course EML 2322l taught by Professor Staff during the Spring '08 term at University of Florida.
 Spring '08
 Staff

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