solutions - 300 TS 2000 103 psi 300 10001 MPa 2000 1000...

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Unformatted text preview: 300 TS 2000 103 psi 300 10001- MPa 2000 1000 0.000 0.020 0 0.000 0.005 0.010 Strain 0.060 1 0.040 Strain 0.015 200 100 200 a tci 100 16 0 0 1000 220 o . o c ifs - —o .00As- EMA 3010 TIME 50 MINUTES; MAE B 211 10.40 - 11.30 am. CLOSED BOOK; ANSWER ALL QUESTIONS; FORMULAS AND CONSTANTS ARE GIVEN BELOW; YOU ARE ALLOWED TO BRI NG A CALCULATOR Hooke's Law a = EE Critical resolved Shear stress = a cos() cos k Fracture toughness = Y a (Tra)° 5 Assume Y = 1.0 1: The figure below shows the engineering tensile stress-strain behavior of alloy steel. Assume that the material has a BCC structure (a) Label (on the curve) and determine the (i) yield strength (at strain offset of 0.0025) and (ii) tensile strength of the alloy steel. Calculate the modulus of elasticity of the material. {13 points k b o o Pex T S= Zoo() N41), (b) Schematically draw the true-stress strain curve of the alloy steel shown in the above figure. Estimate how many slip systems are possible in this material { 10 points} 5,04 S . >Val...
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solutions - 300 TS 2000 103 psi 300 10001 MPa 2000 1000...

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