soln to homework No. 4 2009

soln to homework No. 4 2009 - Homework Problem Ic= To=...

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Homework Problem Ic= 400 W/m2 from Table 3.6 in your text To= 10 deg C Tf,in = 20 deg C Problem 3 Uc= 8 W/m^2K collector efficiency 0.96 Problem 2 0.95 collector efficiency factor this is an av FR= 0.79 could use v 0.56 Gcp= 62.76 4184 J/kgK at 95 deg C 1/Uc= 0.13 F'= 0.83 G = 0.02 kg/sm^2 FR= 0.79 1/(hci*3.1416*D)= D= 0.01 m hci = 300 W/m^2K w= 0.08 m Problem 1 0.93 Collector fin efficiency l'= 0.16 m 0.03 kg/s m= 6.45 0.01 kg/s per tu k= 385 W/m^2K 0.08 gpm/tube t= 0 m problem 6 Ic= 400 W/m2 To= 10 deg C Tf,in = 20 deg C Uc= 8 W/m^2K collector efficiency increases slightly when plate thicknes 0.96 0.95 this is an av FR= 0.81 could use v 0.58 Gcp= 62.76 cp= 4184 J/kgK at 95 deg C 1/Uc= 0.13 F'= 0.85 G = 0.02 kg/sm^2 FR= 0.81 1/(hci*3.1416*D)= D= 0.01 m hci = 300 W/m^2K w= 0.08 m 0.96 l'= 0.16 m m= 4.56 k= 385 W/m^2K t= 0 m problem 8 from table 3.6 in your text Τ s= α s= η c= 1/Uc*(D+2*w* η f)= η f= Τ s= α s= η c= 1/Uc*(D+2*w* η f)= η f=
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Ic= 400 W/m2 To= 10 deg C Tf,in = 20 deg C Uc= 4 W/m^2K collector efficiency increases significantly 0.96 0.95 this is an av FR= 0.89 could use v 0.73 Gcp= 62.76 cp= 4184 J/kgK at 95 deg C 1/Uc= 0.25 F'= 0.92 G = 0.02 kg/sm^2 FR= 0.89 1/(hci*3.1416*D)= D= 0.01 m hci = 300 W/m^2K w= 0.08 m 0.98 l'= 0.16 m m= 3.22 k=
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soln to homework No. 4 2009 - Homework Problem Ic= To=...

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